3n+6b=72,
3n=72-6b
n=24-2b and we are also told that:
4n+5b=66 substituting in n found above into this equation gives
4(24-2b)+5b=66
96-8b+5b=66
-3b=-30
b=10 grams, and since from earlier we saw that n=24-2b
n=24-2(10)
n=24-20
n=4 grams
So the combined mass of one bold and one nut is:
10+4=14 grams
Answer: B. 12 and 64
Step-by-step explanation:
Option A is incorrect because the highest common factor for both numbers would be 38 not 4.
Option B:
Factors of 12 are: 1, 2 , 3, 4, 6, 12
Factors of 64 are: 1, 2, 4, 8, 16, 32 and 64.
<em>Highest factor of both is 4 and they both add up to 76 so option B must be correct. </em>
Answer:
No
Step-by-step explanation:
A^2+b^2=c^2
8^2+15^2=20^2
64+225=400
289=400
289 does not equal 400 so it is not a right triangle
Answer:
where is required question. comment me.
Answer:
A. m^2+7m+10=0
Step-by-step explanation:
This is a problem in pattern matching, and in substituting a variable for a pattern.
(x^2+3)^2 +7x^2 +21 = -10 . . . . . . given
(x^2 +3)^2 +7(x^2 +3) = -10 . . . . . factor the last two terms
m^2 +7m = -10 . . . . . . . . . . . . subsitute m for x^2 +3
m^2 +7m +10 = 0 . . . . . . . . add 10 to both sides; matches A
