Answer:
m∠QPR = 20°
Step-by-step explanation:
If we make a sketch of the triangle, it will be observed, that line R bisects angle P.
Considering Triangle, ΔQPS;
∠QPS=107∘
Considering triangle, QPR;
∠QPR=9x-115∘
Considering triangle, RPS;
∠RPS=4x+27∘
Thus, ∠RPS + ∠QPR = ∠QPS
4x+27° + 9x-115° = 107°
13x - 88° = 107∘
13 x = 107∘ + 88∘
13x = 195°
x = 195°/13
x = 15°
m∠QPR = 9x - 115°
= (9 x 15) - 115°
= 135° - 115°
= 20°
Therefore, m∠QPR = 20°
The sum of the angles of a triangle is 180°. So you can do:
91° + (8x + 3)° + (10x - 4)° = 180° To find x, you need to isolate/get the variable "x" by itself in the equation. First combine like terms (terms that have the same variable and power/exponent]
91 + 3 - 4 + 8x + 10x = 180 (I rearranged for the like terms to be next to each other)
90 + 18x = 180 Subtract 90 on both sides
18x = 90 Divide 18 on both sides to get "x" by itself
x = 5
PROOF
91° + (8x + 3)° + (10x - 4)° = 180° Plug in 5 for "x"
91° + (8(5) + 3)° + (10(5) - 4)° = 180°
91° + (40 + 3)° + (50 - 4)° = 180°
91° + 43° + 46° = 180°
180° = 180°
Answer:
50.24
Step-by-step explanation:
radius R = 2
SA = 4πR^2 = 4π*2^2 = 16π = 16*3.14 = 50.24
Answer:
3/4 of the pie remains
Step-by-step explanation:
Answer:
C) 
The slope of the perpendicular line
Step-by-step explanation:
<u><em>Explanation:-</em></u>
Given that the slope of the given line is
The slope of the perpendicular line
= 
The slope of the perpendicular line
= 
<u><em>Final answer</em></u>
The slope of the perpendicular line
