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Alja [10]
2 years ago
7

1. 8x – 4 = 12x + 12

Mathematics
1 answer:
olga_2 [115]2 years ago
3 0
7(x-2) +3x=46
7x-14+3x=46
10x-14=46
10x=60
X=6
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check the periodic table

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2 years ago
The teacher tells the class the highest marks obtained by a student in her class is twice the lowest marks plus 7 . the highest
Ilya [14]

Answer:

40

Step-by-step explanation:

highest=2(lowest)+7

Replace the variables here:

87=2(lowest)+7

minus 7 on both sides

80=2(lowest)

divide both sides by 2

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7 0
3 years ago
A simple random sample of 90 is drawn from a normally distributed population, and the mean is found to be 138, with a standard d
bagirrra123 [75]

The 90% confidence interval for the population mean of the considered population from the given sample data is given by: Option C:  [130.10, 143.90]

<h3>
How to find the confidence interval for population mean from large samples (sample size > 30)?</h3>

Suppose that we have:

  • Sample size n > 30
  • Sample mean = \overline{x}
  • Sample standard deviation = s
  • Population standard deviation = \sigma
  • Level of significance = \alpha

Then the confidence interval is obtained as

  • Case 1: Population standard deviation is known

\overline{x} \pm Z_{\alpha /2}\dfrac{\sigma}{\sqrt{n}}

  • Case 2: Population standard deviation is unknown.

\overline{x} \pm Z_{\alpha /2}\dfrac{s}{\sqrt{n}}

For this case, we're given that:

  • Sample size n = 90 > 30
  • Sample mean = \overline{x} = 138
  • Sample standard deviation = s = 34
  • Level of significance = \alpha = 100% - confidence = 100% - 90% = 10% = 0.1 (converted percent to decimal).

At this level of significance, the critical value of Z is: Z_{0.1/2} = ±1.645

Thus, we get:

CI = \overline{x} \pm Z_{\alpha /2}\dfrac{s}{\sqrt{n}}\\CI = 138 \pm 1.645\times \dfrac{34}{\sqrt{90}}\\\\CI \approx 138 \pm 5.896\\CI \approx [138 - 5.896, 138 + 5.896]\\CI \approx [132.104, 143.896] \approx [130.10, 143.90]

Thus, the 90% confidence interval for the population mean of the considered population from the given sample data is given by: Option C:  [130.10, 143.90]

Learn more about confidence interval for population mean from large samples here:

brainly.com/question/13770164

3 0
2 years ago
Im a bit confused so please help me quick!
SVETLANKA909090 [29]

Answer:

yes you are correct

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
I NEED IT FAST
djverab [1.8K]

Answer:

  1. r little 4  t little 2
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Step-by-step explanation:

8 0
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