They did not include the constraint for y ≤x+3 on the graph.
See attached picture with added constraint.
Using the 4 points that are given as the solution on the graph, replace t he x and Y in the original equation to solve and see which is the greater value.
Point (0,3) P = -0 +3(3) = 0+9 = 9
Point (1,4) P = -1 + 3(4) = -1 +12 = 11
Point (0,0) P = -0 + 3(0) = 0 + 0 = 0
Point (3,0) P = -3 + 3(0) = -3 + 0 = -3
The correct solution to maximize P is (1,4)
What you do to on side of an equation (=) you must do to the other to keep both sides equal.
r3-2+2=+2 (add 2 to both sides of the equation to simplify the left side)
which becomes
r3=2
r3/3 = 2/3 (divide both sides by 3) Note 3/3 =1 and 1 r is the same as r
which becomes
r=2/3 .
5x=5*2
Y=0 so 5*2=10 +0 =10
Answer:
QUT
Step-by-step explanation: