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german
2 years ago
10

5. Location A is in the center of a large desert. What factor could account for its low annual

Chemistry
1 answer:
Anna11 [10]2 years ago
4 0

Given what we know about the mechanisms surrounding weather, we can confirm that Large deserts receive less rainfall due to the lack of bodies of water and "rainshadows".

  • Rainshadow is a term used to describe the effects of nearby mountains on the rainfall amounts of a desert. The mountain causes the air to rise greatly and lose moisture. This moisture is received by the mountain, <em><u>which means that it does not reach the desert area. </u></em>

  • Another limiting factor for the amount of rainfall received by deserts is the lack of bodies of water in the area. Once a desert is formed, <em>it tends to lack large bodies of water</em>. This limits the rainfall it receives given that there is no water nearby to evaporate and <em><u>cause the formation of clouds. </u></em>

To learn more visit:

brainly.com/question/1051337?referrer=searchResults

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A chemist carefully measures the amount of heat needed to raise the temperature of a 894.0g sample of a pure substance from to −
astraxan [27]

Answer:

C = 0.2349 J/ (g °C)

Explanation:

Mass, m = 894.0g

Initial Temperature = −5.8°C

Final Temperature =  17.5°C

Temperature change = 17.5°C - (−5.8°C) = 23.3

Heat, H = 4.90kJ = 4900 J

Specific heat capacit, C = ?

The relationship between these quantities is given by the equation;

H = mCΔT

C = H / mΔT

C = 4900 / (894)(23.3)

C = 0.2349 J/ (g °C)

4 0
2 years ago
A solution was made by dissolving 5.10 mg of hemoglobin in water to give a final volume of 1.00 ml. the osmotic pressure of this
Assoli18 [71]

The molecular weight of hemoglobin can be calculated using osmotic pressure

Osmotic pressure is a colligative property and it depends on molarity as

πV = nRT

where

π = osmotic pressure

V = volume = 1mL = 0.001 L

n = moles

R = gas constant = 0.0821 L atm / mol K

T = temperature = 25°C = 25 + 273 K = 298 K

Putting values we will get value of moles

moles=\frac{\pi V}{RT}=\frac{0.00195X0.001}{0.0821X298}mol

we know that

moles=\frac{mass}{molarmass}

Therefore

molarmass=\frac{mass}{moles}=\frac{5.10X10^{-3}g}{7.97X10^{-8}}=6.399X10^{4}g

5 0
2 years ago
What is the electron configuration for S-
Sonbull [250]

Answer:

The Electron Configuration for Sulfur(S)= 1s^2  2s^2  2p^6  3s^2  3p^4

Explanation:

Use the sheet attached to help with a future question. (Hint: Follow the red lines). The atomic number will be equal to the number of powers raised.

4 0
3 years ago
Calculate the volume of a gas at a pressure of 150 kpa if its volume at 180 kpa is 1500 L
Anastaziya [24]

Answer: 1800 L

Explanation:

Given that,

Original pressure of gas (P1) = 180 kPa

Original volume of gas (V1) = 1500 L

New pressure of gas (P2) = 150 kPa

New volume of gas (V2) = ?

Since pressure and volume are given while temperature is held constant, apply the formula for Boyle's law

P1V1 = P1V2

180 kPa x 1500 L = 150 kPa x V2

270000 kPa•L = 150 kPa•V2

Divide both sides by 150 kPa

270000 kPa•L/150 kPa = 150 kPa•V2/150 kPa

1800L = V2

Thus, the new volume of the gas is 1800 liters.

8 0
3 years ago
If you breathe normally you have about 0.11 moles of air in your lungs and
Firdavs [7]

Answer:

5.89 Liters

Explanation:

Lung capacity=(2.4/0.11) x 0.27

4 0
3 years ago
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