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german
2 years ago
10

5. Location A is in the center of a large desert. What factor could account for its low annual

Chemistry
1 answer:
Anna11 [10]2 years ago
4 0

Given what we know about the mechanisms surrounding weather, we can confirm that Large deserts receive less rainfall due to the lack of bodies of water and "rainshadows".

  • Rainshadow is a term used to describe the effects of nearby mountains on the rainfall amounts of a desert. The mountain causes the air to rise greatly and lose moisture. This moisture is received by the mountain, <em><u>which means that it does not reach the desert area. </u></em>

  • Another limiting factor for the amount of rainfall received by deserts is the lack of bodies of water in the area. Once a desert is formed, <em>it tends to lack large bodies of water</em>. This limits the rainfall it receives given that there is no water nearby to evaporate and <em><u>cause the formation of clouds. </u></em>

To learn more visit:

brainly.com/question/1051337?referrer=searchResults

You might be interested in
Fluorine has 7 valence electrons what type of bond is likely to form between two atoms?
Semmy [17]
I'm not quiet sure...possibly an ionic bond.
4 0
3 years ago
In air, a silver object can tarnish due to the reaction of silver with hydrogen sulfide, a gas found in the air as a result of c
cluponka [151]

Answer:

The coefficient of Ag is 2.

Explanation:

___Ag (s) + ___H₂S (g) ⇒ ___ Ag₂S (s) + ___ H₂(g)

The Law of Conservation of Matter is also called the law of conservation of mass or the Law of Lomonósov-Lavoisier. This law postulates that "the mass is not created or destroyed, only transformed." This means that the reagents interact with each other and form new products with physical and chemical properties different from those of the reagents because the atoms of the substances are ordered differently. But the amount of matter or mass before and after a transformation (chemical reaction) is always the same, that is, the quantities of the masses involved in a given reaction must be constant at all times, not changing in their proportions when the reaction ends.

In others words, the law of conservation of matter states that since no atom can be created or destroyed in a chemical reaction, the number of atoms that are present in the reagents has to be equal to the number of atoms present in the products.

Then, you must balance the chemical equation. For that, you must first look at the subscripts next to each atom to find the number of atoms in the equation. If the same atom appears in more than one molecule, you must add its amounts :

Left side: 1 Ag, 2 H and 1 S

Right side: 2 Ag, 2 H and 1 S

The coefficients located in front of each molecule indicate the amount of each molecule for the reaction. This coefficient can be modified to balance the equation, just as you should never alter the subscripts.

By multiplying the coefficient mentioned by the subscript, you get the amount of each element present in the reaction.  

You can see that the elements H and S are balanced because we have the same quantity on both sides of the reaction. Then you must balance the Ag, so the reaction is:

2 Ag (s) + 1 H₂S (g) ⇒ 1 Ag₂S (s) + 1 H₂(g)

Now you have:

Left side: 2 Ag, 2 H and 1 S

Right side: 2 Ag, 2 H and 1 S

So, you have the same amount of each element to both of the reaction and this is balanced.

Then, <u><em>the coefficient of Ag is 2.</em></u>

7 0
3 years ago
Three 1.0-l flasks, maintained at 308 k, are connected to each other with stopcocks. initially the stopcocks are closed. one of
Licemer1 [7]

Answer:

0.6103 atm.

Explanation:

  • We need to calculate the vapor pressure of each component after the stopcocks are opened.
  • Volume after the stopcocks are opened = 3.0 L.

<u><em>1) For N₂:</em></u>

P₁V₁ = P₂V₂

P₁ = 1.5 atm & V₁ = 1.0 L & V₂ = 3.0 L.

P₂ of N₂ = P₁V₁ / V₂ = (1.5 atm) (1.0 L) / (3.0 L) = 0.5 atm.

<u><em>2) For H₂O:</em></u>

Pressure of water at 308 K is 42.0 mmHg.

we need to convert from mmHg to atm: <em>(1.0 atm = 760.0 mmHg)</em>.

P of H₂O = (1.0 atm x 42.0 mmHg) / (760.0 mmHg) = 0.0553 atm.

We must check if more 2.2 g of water is evaporated,

n = PV/RT = (0.0553 atm) (3.0 L) / (0.082 L.atm/mol.K) (308 K) = 0.00656 mole.

m = n x cmolar mass = (0.00656 mole) (18.0 g/mole) = 0.118 g.

It is lower than the mass of water in the flask (2.2 g).

<em><u>3) For C₂H₅OH:</u></em>

Pressure of C₂H₅OH at 308 K is 102.0 mmHg.

we need to convert from mmHg to atm: (1.0 atm = 760.0 mmHg).

P of C₂H₅OH = (1.0 atm x 102.0 mmHg) / (760.0 mmHg) = 0.13421 atm.

We must check if more 0.3 g of C₂H₅OH is evaporated,

n = PV/RT = (0.13421 atm) (3.0 L) / (0.082 L.atm/mol.K) (308 K) = 0.01594 mole.

m = n x molar mass = (0.01594 mole) (46.07 g/mole) = 0.7344 g.

<em>It is more than the amount in the flask (0.3 g), so the pressure should be less than 0.13421 atm.</em>

We have n = mass / molar mass = (0.30 g) / (46.07 g/mole) = 0.00651 mole.

So, P of C₂H₅OH = nRT / V = (0.00651 mole) (0.082 L.atm/mole.K) (308.0 K) / (3.0 L) = 0.055 atm.

  • <em>So, </em><em>total pressure</em><em> = </em><em>P of N₂ + P of H₂O + P of C₂H₅OH</em><em> = 0.5 atm + 0.0553 atm + 0.055 atm = </em><em>0.6103 atm</em><em>.</em>
3 0
3 years ago
What happens when the density of a medium increases?
muminat
I believe it’s Refractive index
8 0
2 years ago
muriatic acid is the commercial name for hydrochloric acid that can be purchased from hardware stores as a solution that is 30%(
SSSSS [86.1K]
We have 30% (w/w) HCl this means : 
               100 g solution contains 30 g HCl
               ?? g solution contains 7.5 g HCl
By cross multiplication:
Mass of solution = \frac{100 x 7.5 }{30} = 25 g solution
5 0
3 years ago
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