<h2>sorry I can't help you to solve the equation</h2>
Yes, it is a rational number.
Four types of data (nominal, ordinal, interval, and ratio) that represent values or observations that can be sorted into a category
The answer is 3f
<span>=<span><span>18f</span>+<span>−<span>15f</span></span></span></span><span>=<span>(<span><span>18f</span>+<span>−<span>15f</span></span></span>)</span></span><span>=<span>3<span>f</span></span></span>
Answer:
627200LJ
Step-by-step explanation:
Height of box=5 m
Side of square base=4 m
Volume of rectangular box=![l\times b\times h](https://tex.z-dn.net/?f=l%5Ctimes%20b%5Ctimes%20h)
Using the formula
Volume of rectangular box=![4\times 4\times 5=80m^3](https://tex.z-dn.net/?f=4%5Ctimes%204%5Ctimes%205%3D80m%5E3)
Density of material=![800kg/m^3](https://tex.z-dn.net/?f=800kg%2Fm%5E3)
We know that
![Mass=Density\times volume](https://tex.z-dn.net/?f=Mass%3DDensity%5Ctimes%20volume)
Using the formula
Mass of rectangular box=![80\times 800=64000 kg](https://tex.z-dn.net/?f=80%5Ctimes%20800%3D64000%20kg)
Gravity=![g=9.8m/s^2](https://tex.z-dn.net/?f=g%3D9.8m%2Fs%5E2)
Weight of rectangular box,F=![mg=64000\times 9.8 N](https://tex.z-dn.net/?f=mg%3D64000%5Ctimes%209.8%20N)
Let L be the vertical distance traveled by box
Total work done =![W=F\times displacement](https://tex.z-dn.net/?f=W%3DF%5Ctimes%20displacement)
Therefore,total work done against gravity =
=627200 L J
Hence, the box requires work against gravity=627200LJ