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I am Lyosha [343]
3 years ago
15

Try this hard Math Problem if you dare!!

Mathematics
1 answer:
Dennis_Churaev [7]3 years ago
6 0

Answer:

a. (x - 3)^2 + 16

b. 8(x -7)^2

c. (a^2 - 1)(7x - 6) or (a+1)(a-1)(7x-6)

d. (x^2-4)(x^2+3) or (x-2)(x+2)(x^2+3)

e. (a^n+b^n)(a^n-b^n)(a^{2n} +b^{2n})

Step-by-step explanation:

a.\ (x + 1)^2 - 8(x - 1) + 16

Expand

(x + 1)(x + 1) - 8(x - 1) + 16

Open brackets

x^2 + x + x + 1 - 8x + 8 + 16

x^2 + 2x + 1 - 8x + 24

Collect Like Terms

x^2 + 2x - 8x+ 1  + 24

x^2 - 6x+ 25

Express 25 as 9 + 16

x^2 - 6x+ 9 + 16

Factorize:

x^2 - 3x - 3x + 9 + 16

x(x -3)-3(x - 3) + 16

(x - 3)(x - 3) + 16

(x - 3)^2 + 16

b.\ 8(x - 3)^2 - 64(x-3) + 128

Expand

8(x - 3)(x - 3) - 64(x-3) + 128

8(x^2 - 6x+ 9) - 64(x-3) + 128

Open Brackets

8x^2 - 48x+ 72 - 64x+192 + 128

Collect Like Terms

8x^2 - 48x - 64x+192 + 128+ 72

8x^2 -112x+392

Factorize

8(x^2 -14x+49)

Expand the expression in bracket

8(x^2 -7x-7x+49)

Factorize:

8(x(x -7)-7(x-7))

8((x -7)(x-7))

8(x -7)^2

c.\ 7a^2x - 6a^2 - 7x + 6

Factorize

a^2(7x - 6) -1( 7x - 6)

(a^2 - 1)(7x - 6)

The answer can be in this form of further expanded as follows:

(a^2 - 1^2)(7x - 6)

Apply difference of two squares

(a+1)(a-1)(7x-6)

d.\ x^4 - x^2 - 12

Express x^4 as x^2

(x^2)^2 - x^2 - 12

Expand

(x^2)^2 +3x^2- 4x^2 - 12

x^2(x^2+3) -4(x^2+3)

(x^2-4)(x^2+3)

The answer can be in this form of further expanded as follows:

(x^2-2^2)(x^2+3)

Apply difference of two squares

(x-2)(x+2)(x^2+3)

e.\ a^{4n} -b^{4n}

Represent as squares

(a^{2n})^2 -(b^{2n})^2

Apply difference of two squares

(a^{2n} -b^{2n})(a^{2n} +b^{2n})

Represent as squares

((a^{n})^2 -(b^{n})^2)(a^{2n} +b^{2n})

Apply difference of two squares

(a^n+b^n)(a^n-b^n)(a^{2n} +b^{2n})

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