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3 years ago

What is the name of this ?

Chemistry

1 answer:

nadezda [96]3 years ago

7 0

3-ethyl-4,5-dimethyl-octane

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3 years ago

How many grams of o2 are necessary to react with 212 G of mg 2mg+o2➡2mgo?

gulaghasi [49]

We are given an equation 2Mg+O2-> 2MgO and a starting chemical Mg of about 212 g. In order to solve for the amount of O2 needed, we need the molecular weight of Mg and O2.
Molecular weight:
Mg=24.305 g/mol
O2=16(2)=32 g/mol

Note that for every 1 mol of O2, the amount of Mg must be 2 mol.
So,
g O2 = 212 g Mg x1mo Mgl/24.305 g Mg x1mol O2 /2 mol Mg x 32 g O2/mol O2

gO2=139.56 g

Therefore, 139.56 g of O2 is needed for every 212 g Mg.

7 0

4 years ago

Determine the empirical formula of a compound containing 40. 6 grams of carbon, 5. 1 grams of hydrogen, and 54. 2 grams of oxyge

zavuch27 [327]

The empirical formula is C₂H₃O₂

<h3>What is Empirical formula of a compound ?</h3>

The empirical formula is the simplest whole number ratio of elements present in a compound.

The total molar mass of the compound is 118.084 g/mol.

mass of Carbon present = 40.6

mass of Hydrogen present = 5.1 grams

mass of Oxygen present = 2 grams

Moles of C = 40.6/12 = 3.38

Moles of H = 5.1/1.008 = 5

Moles of Oxygen = 54.2/15.999 = 3.38

Ratio of Moles of C to Oxygen is 1 : 1

Ratio of Moles of C to H is 1/1.5

Multiplying each mole fraction by 2

The empirical formula is C₂H₃O₂

To know more about Empirical Formula

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5 0

2 years ago

Which of the following substance is most likely basic

ehidna [41]

Answer:

Please provide answer options. :)

5 0

3 years ago

If 60 ml of naoh solution neutralizes 40 ml of 0.50 m h2so4, the concentration of the naoh solution is most nearly:

Bad White [126]

<span>The balanced chemical equation for this reaction is:

2NaOH (aq)+H2SO4 (aq) → Na2SO4 (aq)+2H2O (l)

According to question, 60 ml of NaOH solution was used for neutralizing 40 ml of 0.50M H2SO4.

The no. of moles of H2SO4 is calculated using the equation:
mol solute = (molarity) (L soln)

mol H2SO4 = 0.50 M x 0.040 L = 0.02 moles of H2SO4

As per the equation, the number of moles of NaOH used is:

0.02 moles of H2SO4 (2 mol NaOH) (1 mol H2SO4) = 0.04 moles of NaOH

Therefore, using the given volume of NaOH, the concentration or molarity of NaOH can be calculated using the formula :

Molarity = mol solute/L soln = 0.04 mol NaOH/0.06 L = 0.67 M

Therefore, the concentration of NaOH is 0.67 M.</span>

3 0

4 years ago