A 520-gram sample of seawater contains 0.317 moles of NaCl. What is the percent composition of NaCl in the water?
2 answers:
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The given question is incomplete. The complete question is as follows.
From the following formula, calculate the quantities required for each of the following ingredients to make 5 lb. (avoir) of hydrophilic ointment. All values to be in g, do not include units in your submitted answer; use no more than 3 decimal places. Convert using 1 lb = 454 g. Note: all values done by mass, including the water, so this is not a q.s situation (volume is irrelevant).
Methylparaben 0.25 g
Propylparaben 0.15 g
Sodium Lauryl Sulfate 10 g
Propylene Glycol 120 g
Stearyl Alcohol 240 g
White Petrolatum 250 g
Purified Water, to make 1000 g
Explanation:
For the given quantities, the sum is 620.4 g. Now, amount of purified water (to make 1000 g of ointment) is as follows.
1000 g - 620.4 g
= 379.6 g
Now, to make 5 lb we will calculate the quantities as follows.
Formula weight = 1000 g
Therefore, desired quantity is as follows.
5 lb = 5 x 454 g
= 2270 g
Hence, this means the factor is calculated as follows.
= 2.27
Now, we will calculate the quantity of each ingredient using factor 2.27 as follows.
- Methylparaben = 0.25 g x 2.27 = 0.5675 g
- Propylparaben = 0.15 g x 2.27 = 0.3405 g
- Sodium Lauryl Sulfate = 10 g x 2.27 = 22.7 g
- Propylene Glycol = 120 g x 2.27 = 272.4 g
- Stearyl Alcohol = 240 g x 2.27 = 544.8 g
- White Petrolatum = 250 g x 2.27 = 567.5 g
- Purified Water = 379.6 g x 2.27 = 861.692 g