A 520-gram sample of seawater contains 0.317 moles of NaCl. What is the percent composition of NaCl in the water?

Chemistry

2 answers:

agasfer [191]3 years ago

7 0

The answer is in the photo.

Lyrx [107]3 years ago

5 0

Answer:

3.56 %

Explanation:

Percent composition of NaCl = $\frac{mass of NaCl}{mass of sea water }$ x 100

Mass of sea water = 520 g

Moles of NaCl = 0.317 mol

Molar mass of NaCl = 58.44 g/mol

Mass of NaCl = moles of NaCl x Molar mass of NaCl

= 0.317 mol x 58.44 g/mol = 18.52 g

Percent composition of NaCl = $\frac{18.52 g}{520 g}$ x 100 = 3.56 %

You might be interested in

Please help will give 30 points.

vredina [299]

Answer:

Dependent variable: If calcium is given, then bone strength will increase.

Explanation:

3 0

3 years ago

Describe where a hydrogen bond can form among water molecules.

stiv31 [10]

Answer:

In water hydrogen bonding formed between partially negative oxygen and partially positive hydrogen atoms.

Explanation:

Hydrogen bond is a partially electrostatic attraction between hydrogen (H), which is bonded to a more electronegative atom such as nitrogen (N), oxygen (O) or fluorine (F), and another adjacent atom bearing a lone pair of electrons.

In water molecule hydrogen and oxygen have difference in electronegativity, due to which dipoles are form. One is partial positive on hydrogen atom and other is partial negative on oxygen atom. The electrostatic attraction occur between two oppositely charged poles which is known as hydrogen bonding.