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cricket20 [7]
3 years ago
5

A 520-gram sample of seawater contains 0.317 moles of NaCl. What is the percent composition of NaCl in the water?

Chemistry
2 answers:
agasfer [191]3 years ago
7 0

The answer is in the photo.

Lyrx [107]3 years ago
5 0

Answer:

3.56 %

Explanation:

Percent composition of NaCl =  \frac{mass of NaCl}{mass of sea water  } x 100

Mass of sea water = 520 g  

Moles of NaCl = 0.317  mol

Molar mass of NaCl = 58.44 g/mol

Mass of NaCl = moles of NaCl x Molar mass of NaCl  

                       =   0.317  mol x 58.44 g/mol  = 18.52 g

Percent composition of NaCl = \frac{18.52 g}{520 g}  x 100 = 3.56 %

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This is a very interesting question because it tests your understanding of what it means to have a dynamic equilibrium going on in solution.

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