This has to be more specific..........but the name of the cell is called a galvanic cell and cations react at the cathode. Hope this helps.
The molarity of dilute solution is calculated using M1V1= M2V2 formula
M1 = molarity 1 ( 6.0 m)
V1 = volume 1 ( 445ml)
V2= volume 2 (2.5 x1000 = 2500ml)
M2= molarity 2 = ?
M2 is therefore = M1V1/V2
= 445 ml x 6.0 M/ 2500ml = 1.07 M
The complete reaction of the problem, for better illustration, is
FeO(s) + CO(g) <--> Fe(s) + CO2(g)
The double-tailed arrow signifies that the reaction is in a dynamic chemical equilibrium. When the system is in equilibrium, the forward and the backward reaction rates have an equal ratio of Kp = 0.403 at 1000°C. The formula for Kp is
Kp = [partial pressure of products]/[partial pressure of reactants]
So, first, let's find the partial pressure of the compounds in the reaction.
FeO(s) + CO(g) <--> Fe(s) + CO2(g)
Initial x 1.58 0 0
Change -1.58 -1.58 +1.58 +1.58
------------------------------------------------------------------
Equilbrium x-1.58 0 1.58 1.58
Kp = [(1.58)(1.58)]/[(x-1.58)] = 0.403
x = 7.77 atm (this is the amount of excess FeO)
Therefore, the partial pressure of CO2 at equilibrium is 1.58 atm. There is no more CO because it has been consumed due to excess FeO.
Atomic number is called the number written to the left of a chemical symbol or formula
Answer:
3.47 × 10¹ M⁻¹ h⁻¹
Explanation:
From the question, it's clearly depicted that it is a second order reaction rate.
NOW, rate constant for second order reaction can be given as:
k(t)=
Given that:
t = 24 hours
Let the initial concentration of reactant
Final concentration
∴
k(t)=
k(24)hours = 833.33 M⁻¹
k =
k = 34.72 M⁻¹ h⁻¹
k = 3.472 × 10¹ M⁻¹ h⁻¹
∴ the value of the rate constant (k) = 3.472 × 10¹ M⁻¹ h⁻¹