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Veronika [31]
3 years ago
14

If 445 ml of 6.0 M HNO3 is diluted to 2.5 L, what is the molarity of the diluted solution?

Chemistry
1 answer:
Amiraneli [1.4K]3 years ago
6 0
  The  molarity  of  dilute  solution   is  calculated  using  M1V1= M2V2   formula
M1 = molarity 1 (  6.0 m)
V1  =  volume  1 ( 445ml)
V2= volume  2 (2.5  x1000  = 2500ml)
M2=  molarity 2 =  ?

M2  is  therefore = M1V1/V2
=  445  ml  x   6.0  M/  2500ml  = 1.07 M
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Water: solute
alcohol: solvent

solution: a uniform mixture that has a solvent and at least one solute
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4 years ago
Distinguish between zinc nitrate and lead nitrate ​
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Explanation:

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3 years ago
Calculate the mass of potassium acid phthalate (HKC8H4O4) that will require about 15 mL of the approximately 0.1 M NaOH solution
LuckyWell [14K]

Answer:

0.31 g

Explanation:

The equation of the reaction;

HKC8H4O4(aq) + NaOH(aq) ----> Na(KC8H4O4)(aq) + H2O(l)

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6 0
3 years ago
a sample of a gas has a volume kf 640 cm^{3} at 100°c and 1490 mmhg,what would be its volume at stp?​
scoundrel [369]

Answer:

V₂ = 918.1 cm³

Explanation:

Given data:

Initial volume = 640 cm³

Initial temperature = 100°C (100+273 = 373 K)

Initial pressure = 1490 mmHg (1490 /760 = 1.96 atm)

Final volume = ?

Final temperature = 273 K

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Formula:  

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

now we will put the values in formula.

V₂ = P₁V₁ T₂/ T₁ P₂  

V₂ = 1.96 atm × 640 cm³ × 273 K / 373 K × 1 atm

V₂ = 342451.2 atm .cm³ . K / 373 K. atm

V₂ = 918.1 cm³

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3 years ago
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