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Luda [366]
3 years ago
14

In the 19th century James Joule, an English scientist, was the first to recognize the mechanical equivalent of heat as a specifi

c form of the general rule of the conversion of one form of energy to another. Which fact can be explained with the help of this law?
Chemistry
1 answer:
otez555 [7]3 years ago
8 0

Answer:

The law of conservation of energy is a law of science that states that energy cannot be created or destroyed, but only changed from one form into another or transferred from one object to another. This law is taught in physical science and physics classes in middle schools and high schools, and is used in those classes as well as in chemistry classes.

Explanation:

The law of conservation of energy can be seen in these everyday examples of energy transference:

Water can produce electricity. Water falls from the sky, converting potential energy to kinetic energy. This energy is then used to rotate the turbine of a generator to produce electricity. In this process, the potential energy of water in a dam can be turned into kinetic energy which can then become electric energy.

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There are two binary compounds of mercury and oxygen. heating either of them results in the decomposition of the compound, with
grandymaker [24]

\text{Hg} \text{O} and \text{Hg}_{2} \text{O}.

Assuming complete decomposition of both samples,

  • m(\text{Hg}) = m(\text{residure})
  • m(\text{O}) = m(\text{loss})

First compound:

  • m(\text{O}) = m(\text{loss}) = 0.6498 - 0.6018 = 0.048 \; g
  • m(\text{Hg}) = m(\text{residure}) = 0.6018 \; g

n = m/M; 0.6498 \; g of the first compound would contain

  • n(\text{O atoms}) = 0.048 \; g  / 16 \; g \cdot mol^{-1}= 0.003 \; mol
  • n(\text{Hg atoms}) = 0.6018 \; g  / 200.58 \; g \cdot mol^{-1}= 0.003 \; mol

Oxygen and mercury atoms seemingly exist in the first compound at a 1:1 ratio; thus the empirical formula for this compound would be \text{Hg} \text{O} where the subscript "1" is omitted.

Similarly, for the second compound

  • m(\text{O}) = m(\text{loss}) = 0.016 \; g
  • m(\text{Hg}) = m(\text{residure}) = 0.4172 - 0.016 = 0.4012  \; g

n = m/M; 0.4172 \; g of the first compound would contain

  • n(\text{O atoms}) = 0.016 \; g  / 16 \; g \cdot mol^{-1}= 0.001 \; mol
  • n(\text{Hg atoms}) = 0.4012 \; g  / 200.58 \; g \cdot mol^{-1}= 0.002 \; mol

n(\text{Hg}) : n(\text{O}) \approx  2:1 and therefore the empirical formula

\text{Hg}_{2} \text{O}.

8 0
3 years ago
A buffer solution contains 0.345 M acetic acid and 0.377 M sodium acetate . If 0.0613 moles of potassium hydroxide are added to
melamori03 [73]

Answer:

pH = 5.54

Explanation:

The pH of a buffer solution is given by the <em>Henderson-Hasselbach (H-H) equation</em>:

  • pH = pKa + log\frac{[CH_3COO^-]}{[CH_3COOH]}

For acetic acid, pKa = 4.75.

We <u>calculate the original number of moles for acetic acid and acetate</u>, using the <em>given concentrations and volume</em>:

  • CH₃COO⁻ ⇒ 0.377 M * 0.250 L = 0.0942 mol CH₃COO⁻
  • CH₃COOH ⇒ 0.345 M * 0.250 L = 0.0862 mol CH₃COOH

The number of CH₃COO⁻ moles will increase with the added moles of KOH while the number of CH₃COOH moles will decrease by the same amount.

Now we use the H-H equation to <u>calculate the new pH</u>, by using the <em>new concentrations</em>:

  • pH = 4.75 + log\frac{(0.0942+0.0613)mol/0.250L}{(0.0862-0.0613)mol/0.250L} = 5.54
6 0
3 years ago
What happens when energy is added to each state?
e-lub [12.9K]

Answer:

One change of state happens when you add energy to the substance. This change of state is called melting. By adding energy to the molecules in a solid the molecules begin to move quicker and can break away from the other molecules. ... The temperature at which a substance goes from a solid to a liquid is it melting point.

5 0
3 years ago
A sample of gas has a volume of 100. L at 17 °C and 800. torr. To what temperature must the gas be cooled in order for its volum
Romashka [77]

Answer:

108.81 K

Explanation:

First convert 17 °C to Kelvin:

  • 17 + 273.16 = 290.16 K

Assuming ideal behaviour, we can solve this problem by using the<em> combined gas law</em>, which states that at constant composition:

  • P₁V₁T₂=P₂V₂T₁

Where in this case:

  • P₁ = 800 torr
  • V₁ = 100 L
  • T₂ = ?
  • P₂ = 600 torr
  • V₂ = 50 L
  • T₁ = 290.16 K

We <u>input the data</u>:

  • 800 torr * 100 L * T₂ = 600 torr * 50 L * 290.16 K

And <u>solve for T₂</u>:

  • T₂ = 108.81 K
6 0
3 years ago
How many values of these of these trials can be considered accurate?
Gnoma [55]

Answer:

go to google

Explanation:it all ways work

6 0
3 years ago
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