Well, if you look at group 1 of the periodic table, you will notice a thrend. All elements in group 1 have 1 valence / outer electron. Then you look at period 2, 3, 4 and so on, you will see that the group number corresponds the number of valence/ outershell electrons. Hence, the group determines the electron(s) on the outershell.
The composition, in atom percent, of an alloy that consists of 30 wt% Zn and 70 wt% Cu is 29.4 at % and 70.6 at % for Zn and Cu respectively.
<h3>How to convert weight % to atom %?</h3>
The weight percentage of an element can be converted to atom percentage as follows:
- C(Zn) = C1A2 / (C2A1) + (C1A2) × 100
- C(Cu) = C2A1 / (C1A2) + (C2A1) × 100
Where;
- C1 = 30
- C2 = 70
- A1 = 65.4g/mol
- A2 = 63.55g/mol
- C(Zn) = {30*63.55} / (70*65.4) + (30*63.55) × 100
- C(Cu) = {70*65.4} / (30*63.55) + (70*65.4) × 100
- C(Zn) = 29.4 at %
- C(Cu) = 70.6 at %
Therefore, the composition, in atom percent, of an alloy that consists of 30 wt% Zn and 70 wt% Cu is 29.4 at % and 70.6 at % for Zn and Cu respectively.
Learn more about atomic percent at: brainly.com/question/10018123
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Answer:
I Think It's The Second One
Tell Me If I'm Wrong
Answers:
1.
The mole ratio of AlCl₃ to Cl₂ is 2 : 3. This means for production of every 2 moles of AlCl₃ 3 moles of Cl₂ is consumed. Hence, if 3 moles of AlCl₃ is produced then Cl₂ consumed is,
= 3 × 3 / 2
= 4.5 moles of Cl₂
2.
Mole ratio of C₃H₈ to CO₂ is 1 : 3.
Hence, 0.5 moles of C₃H₈ will produce 1.5 moles of CO₂.
Also,
At STP one mole of an ideal gas occupied 22.4 L of volume. Hence, 1.5 moles of CO₂ gas will occupy,
Volume = 1.5 mol × 22.4 L/mol
Volume = 33.6 L of CO₂