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Bingel [31]
3 years ago
7

What is the value of x ??

Mathematics
2 answers:
Alika [10]3 years ago
7 0
8................................
olga55 [171]3 years ago
6 0

Answer:

b. 8

Step-by-step explanation:

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mel-nik [20]

Answer:

-3=3x+12

Step-by-step explanation:

3 0
3 years ago
Please help asap !!
kaheart [24]

Answer:

y = x + 1.5

Step-by-step explanation:

When you look at the table, all the y values are 1.5 more than the x values. When you write this as an equation it becomes y = x + 1.5

3 0
3 years ago
Simplify the complex numbers using de Moivre's Theorem and match them with their solutions.
alexandr1967 [171]

For the numbers in a+bi form, convert to polar form:


1+i=\sqrt2\dfrac{1+i}{\sqrt2}=\sqrt2\left(\cos\dfrac\pi4+i\sin\dfrac\pi4\right)

By DeMoivre's theorem,

(1+i)^5=(\sqrt2)^5\left(\cos\dfrac{5\pi}4+i\sin\dfrac{5\pi}4\right)=4\sqrt2\dfrac{-1-i}{\sqrt2}=-4-4i


-1+i=\sqrt2\dfrac{-1+i}{\sqrt2}=\sqrt2\left(\cos\dfrac{3\pi}4+i\sin\dfrac{3\pi}4}\right)

\implies(-1+i)^6=(\sqrt2)^6\left(\cos\dfrac{18\pi}4+i\sin\dfrac{18\pi}4\right)=8i


\sqrt3+i=2\dfrac{\sqrt3+i}2=2\left(\cos\dfrac\pi6+i\sin\dfrac\pi6\right)

\implies2(\sqrt3+i)^{10}=2^{11}\left(\cos\dfrac{10\pi}6+i\sin\dfrac{10\pi}6\right)=2^{11}\dfrac{1-i\sqrt3}2=2^{10}(1-i\sqrt3)


For the numbers already in polar form, DeMoivre's theorem can be applied directly:


2\left(\cos20^\circ+i\sin20^\circ\right)^3=2\left(\cos60^\circ+i\sin60^\circ\right)=2\dfrac{1+i\sqrt3}2=1+i\sqrt3


2\left(\cos\dfrac\pi4+i\sin\dfrac\pi4\right)^4=2(\cos\pi+i\sin\pi)=-2


At second glance, I think the 2s in the last two numbers should also be getting raised to the 3rd and 4th powers:


\left(2(\cos20^\circ+i\sin20^\circ)\right)^3=8\left(\cos60^\circ+i\sin60^\circ\right)=4+4\sqrt3

\left(2\left(\cos\dfrac\pi4+i\sin\dfrac\pi4\right)\right)^4=16(\cos\pi+i\sin\pi)=-16

4 0
3 years ago
Which relationship has a zero slope? 55 Points!
pshichka [43]

Answer:

b

Step-by-step explanation:

6 0
3 years ago
Find an expression for the number of squares in the nth pattern of the sequence. I noticed that the number of squares you add in
Morgarella [4.7K]

Answer:

make clear the question please

3 0
4 years ago
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