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3 years ago

PLEASE HELP ME WHAT IS THE ANWSER

Mathematics

2 answers:

IceJOKER [234]3 years ago

6 0

Answer:

Vertical Angles: a and c , d and b

m<b= 82⁰ , m<c=98⁰ , m<d=82⁰

Adjacent Angles: a and b , b and c , c and d ,d and a

correct me if im wrong

mariarad [96]3 years ago

3 0

Answer:

c is the same angle as a

b and d are the same as the other

and together the are what's left from 360° after a and c got their share

360 -98 -98 = b + d

makes

164 = b + d

since they are of equal value, just decide 164 by 2 and you got b and d at once

pls brainliest

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Simplify the expression and find its value when a = 5 and b = -3 .

kenny6666 [7]

Answer:

$\sf\longmapsto \: 38$

Step by step explanation:

$\sf\longmapsto \: 2a² + 2ab +3-ab$

$\sf\longmapsto \: 2a² + 3 + ab (2-1)$

$\sf\longmapsto \: 2a² + 3 + ab (1)$

$\sf\longmapsto \: 2a² + 3 + ab$

$\sf\longmapsto \: 2a² + ab + 3$

Putting a = 5 b = - 3

$\sf\longmapsto \: 2(5) {}^{2} + (5) (-3) +3$

$\sf\longmapsto \: 2 (25) - 15 + 3$

$\sf\longmapsto \: 50 - 12$

$\sf\longmapsto \: 38$

7 0

3 years ago

Read 2 more answers

A national college researcher reported that 65% of students who graduated from high school in 2012 enrolled in college. Twenty n

Usimov [2.4K]

Answer:

a) The probability that exactly 17 of them enroll in college is 0.116.

b) The probability that more than 14 enroll in college is 0.995.

c) The probability that fewer than 11 enroll in college is 0.001.

d) It would be be unusual if more than 24 of them enroll in college since the probability is 0.009.

Step-by-step explanation:

We can model this with a binomial distribution, with n=29 and p=0.65.

The probability that k students from the sample who graduated from high school in 2012 enrolled in college is:

$P(x=k) = \dbinom{n}{k} p^{k}(1-p)^{n-k}\\\\\\P(x=k) = \dbinom{29}{k} 0.65^{k} 0.35^{29-k}\\\\\\$

a) The probability that exactly 17 of them enroll in college is:

$P(x=17) = \dbinom{29}{17} p^{17}(1-p)^{12}=51895935*0.0007*0=0.116\\\\\\$

b) The probability that more than 14 of them enroll in college is:

$P(X>14)=\sum_{15}^{29} P(X=k_i)=1-\sum_{0}^{14} P(X=k_i)\\\\\\P(x=0)=0\\\\P(x=1)=0\\\\P(x=2)=0\\\\P(x=3)=0\\\\P(x=4)=0\\\\P(x=5)=0\\\\P(x=6)=0\\\\P(x=7)=0\\\\P(x=8)=0\\\\P(x=9)=0\\\\P(x=10)=0.001\\\\P(x=11)=0.002\\\\P(x=12)=0.005\\\\P(x=13)=0.013\\\\P(x=14)=0.027\\\\\\P(X>14)=1-0.005=0.995$

c) Using the probabilities calculated in the point b, we have:

$P(X$

d) The probabilities that more than 24 enroll in college is:

$P(X>24)=\sum_{25}^{29}P(X=k_i)\\\\\\ P(x=25) = \dbinom{29}{25} p^{25}(1-p)^{4}=23751*0*0.015=0.007\\\\\\P(x=26) = \dbinom{29}{26} p^{26}(1-p)^{3}=3654*0*0.043=0.002\\\\\\P(x=27) = \dbinom{29}{27} p^{27}(1-p)^{2}=406*0*0.123=0\\\\\\P(x=28) = \dbinom{29}{28} p^{28}(1-p)^{1}=29*0*0.35=0\\\\\\P(x=29) = \dbinom{29}{29} p^{29}(1-p)^{0}=1*0*1=0\\\\\\\\P(X>24)=0.007+0.002+0+0+0=0.009$

6 0

3 years ago

Lines a and b are parallel <br><br>what is the measurement of angle s?<br>

Novosadov [1.4K]

Answer:

22 degrees

Step-by-step explanation:

158 x 2 is 316

360 - 316 = 44

44 / 2 = 22

and both are the same angles for each set of angles.

6 0

3 years ago

X+3=5 . Find x in the given equation

Oduvanchick [21]

Answer:

Step-by-step explanation:

x + 3 = 5

x = 5 - 3

x = 2

Therefore, x=2 in the given equation

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3 years ago

Read 2 more answers

Can you show the work

atroni [7]

Probably means you need to show the workings out to the questions your answering. But that's all I can give you based on what you have posted.

7 0

4 years ago