Force=mass*acceleration
F=ma
F=25*5
F=100 N
C and d have the same amount of protons and electrons
Explanation:
It is given that,
Displacement of the delivery truck,
(due east)
Then the truck moves,
(due south)
Let d is the magnitude of the truck’s displacement from the warehouse. The net displacement is given by :


d = 4.03 km
Let
is the direction of the truck’s displacement from the warehouse from south of east.


So, the magnitude and direction of the truck’s displacement from the warehouse is 4.03 km, 37.4° south of east.
Answer:
304 meters downstream
Explanation:
The given parameters are;
The speed of the swimmer = 2.00 m/s
The width of the river = 73.0 m
The speed of the river = 8.00 m/s
Therefore;
The direction of the swimmer's resultant velocity = tan⁻¹(8/2) ≈ 75.96° downstream
The distance downstream the swimmer will reach the opposite shore = 4 × 73 = 304 m downstream
The distance downstream the swimmer will reach the opposite shore = 304 m downstream