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gogolik [260]
3 years ago
9

A 10 kg block is pushed with a constant horizontal force of 20 n against a constant horizontal frictional force of 10 n. What is

the acceleration of the block?
Physics
1 answer:
kari74 [83]3 years ago
6 0

Answer:

The acceleration would be a=1 m/s^2. Let's explain why.

Explanation:

Let's say the block is □

20N→□    Block is pushed with a constant horizontal force of 20N

□←10N     It is known that frictional force is the <u>opposite way</u> of the movement

So it is safe to say that there is 10 N force trying to stop the block.

In this case our net force is F_{net} = 20-10=10N

According to <u>Newton's second motion law</u>

F=m.a (m=mass, F=force, a=acceleration

F_{net} =10=10.a → a=1\frac{m^{2} }{s}

As an extra information the block also applies gravitational m.g force down but since there is no other force applies in the vertical way, ground compansate the force.

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1.41 m/s^2

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a_c=\frac{(12.8 m/s)^2}{140 m}=1.17 m/s^2

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A plane travels down a runway 2750 m before it lifts off at an angle of 37 degrees from the horizontal. The plane has traveled 1
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P = (0 + 2750m, 0) = (2750m, 0).

"it lifts off at an angle of 37 degrees from the horizontal. The plane has traveled 1.8 km since its wheels left the ground."

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x = 1.8km*cos(37°) = 1.438km

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And the displacement will be:

D = √( (4.188km - 0)^2 + (1.083 - 0)^2) = 4.236km

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