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3 years ago

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A 10 kg block is pushed with a constant horizontal force of 20 n against a constant horizontal frictional force of 10 n. What is

the acceleration of the block?

1 answer:

kari74 [83]3 years ago

6 0

Answer:

The acceleration would be a=1 m/s^2. Let's explain why.

Explanation:

Let's say the block is □

20N→□ Block is pushed with a constant horizontal force of 20N

□←10N It is known that frictional force is the <u>opposite way</u> of the movement

So it is safe to say that there is 10 N force trying to stop the block.

In this case our net force is $F_{net} = 20-10=10N$

According to <u>Newton's second motion law</u>

$F=m.a$ (m=mass, F=force, a=acceleration

$F_{net} =10=10.a$ → $a=1\frac{m^{2} }{s}$

As an extra information the block also applies gravitational m.g force down but since there is no other force applies in the vertical way, ground compansate the force.

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To calculate the mass the engine burns each seconds, we use the formula below.

Formual:

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Where:

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From the question,

Given:

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You leave the doctor's office after your annual checkup and recall that you weighed 688 N in her office. You then get into an el

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Answer:

$a=0.5418\ m.s^{-2}$ upwards

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Explanation:

Given:

weight of the person, $w=688\ N$

So, the mass of the person:

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Now the corresponding acceleration:

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3 years ago

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