0.0000004. since it is 10^-7 (note the negative), you would move thedecimal point 7 places to the left.
Answer:
23376 days
Explanation:
The problem can be solved using Kepler's third law of planetary motion which states that the square of the period T of a planet round the sun is directly proportional to the cube of its mean distance R from the sun.
where k is a constant.
From equation (1) we can deduce that the ratio of the square of the period of a planet to the cube of its mean distance from the sun is a constant.
Let the orbital period of the earth be and its mean distance of from the sun be .
Also let the orbital period of the planet be and its mean distance from the sun be .
Equation (2) therefore implies the following;
We make the period of the planet the subject of formula as follows;
But recall that from the problem stated, the mean distance of the planet from the sun is 16 times that of the earth, so therefore
Substituting equation (5) into (4), we obtain the following;
cancels out and we are left with the following;
Recall that the orbital period of the earth is about 365.25 days, hence;
guaranteeing freedom of speech, press, assembly, and exercise of religion
I am a girl and i have a virgina and im 13 tho so dont touch me lolz mark brainly
Answer:
stryo: 1
wood: 1
ice: 1
brick: 2
aluminum: 2.7
Explanation:
d= mass/ total volume
(fyi: for aluminum, they did the subtraction wrong to find the total volume. it is actually 5 or 5.00)