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netineya [11]
3 years ago
8

15 beats are heard in 5 seconds when a piano key and a tuning fork of slightly higher frequency (440 Hz) are struck at the same

time. What is the frequency of the sound emitted by the piano key?
Physics
1 answer:
chubhunter [2.5K]3 years ago
6 0

Answer:

437Hz

Explanation:

if two sound waves have a little difference in frequencies f_{a}     and f_{a}       interfere, the resulting sound wave produces a beat.

Given:

f_{a}=440Hz

 f_{b}=frequency\ of\ the\ sound\ emitted by\ the\ piano\ key

f_{beat}=frequency\ of\ beat

where

f_{beat}=\frac{number\ of\ beat}{time}

f_{beat}=\frac{15beats}{5}=3Hz

f_{beat}=f_{a}-f_{b}

f_{b}=f_{a}-f_{beat} = 440Hz - 3Hz = 437Hz

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A girl swings on a playground swing in such a way that at her highest point she is 4.1 m from the ground, while at her lowest po
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Answer:

V1 =8.1 m/s

Explanation:

height at highest point (h2) = 4.1 m

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acceleration due to gravity (g) = 9.8 m/s^{2}

from conservation of energy, the total energy at the lowest point will be the same as the total energy at the highest point. therefore

mgh1 + 0.5mV1^{2} = mgh2 + 0.5mV2^{2}

where

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  • speed at lowest point = V1
  • mass of the girl and swing = m
  • at the highest point, the  speed is minimum (V1 = 0)
  • at the lowest point the speed is maximum (V2 is the maximum speed)
  • therefore the equation becomes mgh1 + 0.5mV1^{2} = mgh2

      m(gh1 + 0.5V1^{2}) = m(gh2)

      gh1 + 0.5V1^{2} = gh2

      V1 = \sqrt{\frac{gh2 - gh1}{0.5}}

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