P1. if your school makes $0.72 profit on every 6 raffle tickets sold, how much will it make when it sells the 11th ticket

Mathematics

1 answer:

Ahat [919]3 years ago

4 0

Answer:

Part 1 = $1.32

Step-by-step explanation:

.72 divided by 6 is 12. So they make 12 cents per ticket, so that means you would have to do 12 times 11 and that should get you 132 cents and that is equivalent to $1.32.

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The area of each triangular face of this right triangular prism is 8cm^2(squared).

otez555 [7]

Nothing is shown.
The triangle is a right triangle, 9, 12 & 15.
The triangle's area = b*h/2 = 9*12/2 = 54 sq meters each end.

------------
The 3 rectangles are 10 by 9, 12 & 15
Area of the 3 = 10*(9 + 12 + 15) = 360 sq meters
-----
Total area = 360 + 2*54
= 468 sq meters

8 0

3 years ago

Two systems of equations are shown below:

Sati [7]

System A:
6x + y = 2
-x - y = -3

System B:
2x - 3y = -10
-x-y = -3

Solve:
System A:
6x + y = 2
y = 2 - 6x
-x - (2-6x) = -3
-x - 2 + 6x = -3
5x = -3 + 2
5x = -1
x = -1/5
y = 2 - 6(-1/5)
y = 2 + 6/5
y = 2 + 1.2
y = 3.2 System A: x = -1/5 or -0.2 ; y = 3 1/5 or 3.2

System B:
2x - 3y = -10
2x = -10 + 3y
x = -5 + 1.5y
-x - y = -3
-(-5 + 1.5y) -y = -3
5 - 1.5y - y = -3
-2.5y = -3 - 5
-2.5y = -8
y = 3.2
x = -5 + 1.5(3.2)
x = -5 + 4.8
x = -0.2 System B: x = -0.2 ; y = 3.2

<span>B) They will have the same solution because the first equations of both the systems have the same graph.</span>

6 0

3 years ago

Read 2 more answers

A 12,000-lb killer whale might eat as much as 14,000 lb of fish per month (assume a 30-day month). If the average weight of a ce

brilliants [131]

Answer:

2196 fish

Step-by-step explanation:

Weight of fish that the killer whale might eat in a month (30 days) = 14,000 lb

Weight of the fish that killer whale might eat in a day = $\frac{14000}{30} = \frac{1400}{3}$ lb.

Average weight of the fish that killer whale eats = 3.4 oz

Since,

1 pound(lb) = 16 ounces(oz)

So,

Weight of the fish that killer whale might eat in a day in ounces(oz) = $\frac{1400}{3} \times 16=\frac{22400}{3}$ oz

Since, a certain fish weighs 3.4 oz, in order to find the number of fish that killer whale must eat, we must divide the total weight in ounces by 3.4 ounces.

So, the number of fish that killer whale would eat = $\frac{22400}{3} \div 3.4 = 2196$ fish