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3 years ago

Which of the following tables of values could not represent a function?

Mathematics

2 answers:

horrorfan [7]3 years ago

7 0

Answer:

Step-by-step explanation:

SVETLANKA909090 [29]3 years ago

5 0

Answer:

B) is not a function

Step-by-step explanation:

For an table to be a function the y axis all have to be different from each other but on B it is not, it is only 1, therefore B is not a function

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Find the sum of -6/ab + a^2/b^2

Ymorist [56]

Answer:

$\frac{1}{ab^{2} }$ (a³ - 6b)

Step-by-step explanation:

$\frac{-6}{ab} + \frac{a^{2} }{b^{2} }$

= $\frac{-6b + a^{3} }{ab^{2} }$

= $\frac{1}{ab^{2} }$ (a³ - 6b)

4 0

3 years ago

The measures of 5 of the Interior angles of a hexagon are: 115.125", 85", 150", and 170". What is the measure of the

levacccp [35]

The measure of the largest exterior angle of hexagon is 105

<u>Solution:</u>

Given, The measures of 5 of the Interior angles of a hexagon are: 115.125", 85", 150", and 170".

We have to find what is the measure of the largest exterior angle?

Now let us find the 6th interior angle,

We know that, sum of interior angles of hexagon = 720 degrees

115 + 125 + 85 + 150 + 170 + 6th angle = 720

645 + 6th angle = 720

6th angle = 720 – 645

6th angle = 75 degrees

Now we have to find the largest exterior angle, we know that, the complement of largest exterior angle will be smallest interior angle.

So, here smallest interior angle is 75

sum of interior and exterior angle equals to 180

Hence interior angle + exterior angle =180

Then, 75 + exterior angle = 180

Exterior angle = 180 – 75 = 105.

Hence, exterior angle is 105 and 1st option is correct.

4 0

3 years ago

How do you classify a triangle by its sides

erik [133]

Triangle classification by sides would be scalene, no congruent sides; isosceles, at least 2 congruent sides; equilateral, 3 congruent sides.

6 0

4 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=4x%5E%7B0%7D%20x16x%5E%7B0%7D" id="TexFormula1" title="4x^{0} x16x^{0}" alt="4x^{0} x16x^{0}"

statuscvo [17]

Answer:

Step-by-step explanation:

its just how it is

8 0

3 years ago

According to data from a medical association, the rate of change in the number of hospital outpatient visits, in millions, in

GaryK [48]

Answer:

a) $f(t)=0.001155[\frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}]+264,034,000$

b) f(t=2015) = 264,034,317.7

Step-by-step explanation:

The rate of change in the number of hospital outpatient visits, in millions, is given by:

$f'(t)=0.001155t(t-1980)^{0.5}$

a) To find the function f(t) you integrate f(t):

$\int \frac{df(t)}{dt}dt=f(t)=\int [0.001155t(t-1980)^{0.5}]dt$

To solve the integral you use:

$\int udv=uv-\int vdu\\\\u=t\\\\du=dt\\\\dv=(t-1980)^{1/2}dt\\\\v=\frac{2}{3}(t-1980)^{3/2}$

Next, you replace in the integral:

$\int t(t-1980)^{1/2}=t(\frac{2}{3}(t-1980)^{3/2})- \frac{2}{3}\int(t-1980)^{3/2}dt\\\\= \frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}+C$

Then, the function f(t) is:

$f(t)=0.001155[\frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}]+C'$

The value of C' is deduced by the information of the exercise. For t=0 there were 264,034,000 outpatient visits.

Hence C' = 264,034,000

The function is:

$f(t)=0.001155[\frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}]+264,034,000$

b) For t = 2015 you have:

$f(t=2015)=0.001155[\frac{2}{3}(2015)(2015-1980)^{1/2}-\frac{4}{15}(2015-1980)^{5/2}]+264,034,000\\\\f(t=2015)=264,034,317.7$

3 0

3 years ago