Answer:
12m/s
Explanation:
Using the equation of motion
v = u + at
Given that
u = 0m/s
a = 2m/s²
time t = 6s
Substitute the given values into the expression
v = 0 + 2(6)
v = 0+12
v = 12m/s
Hence the required velocity is 12m/s
Total work energy on the input side is WE = Fs; where F is a force acting on a mass to push it s distance. This is the so-called work function. Let fs = we, which is the work energy (useful energy) attained as output when WE is input.
<span>From the conservation of energy WE = Fs = fs - kNs = Total Output energy. Net force f = F - kN where kN is friction force acting against the pushing (input) force F. In the real world, there is always friction at some level. That is kN > 0 always. </span>
<span>Thus Fs = (F - kN)s; kNs = the energy lost to friction where k is the friction coefficient and N is the normal force on the surface(s) where the friction is generated. By definition, efficiency = fs/Fs = useful work/work input. Clearly fs = Fs - kN < Fs . Thus efficiency = fs/Fs < 1.00, which means output fs < Fs the input whenever kN > 0, which in the real world it always is. </span>
<span>The short answer is...output is always less than input because of friction and, sometimes, other losses like wind drag (which is a form of friction anyway).</span>
Answer:
on an average, <em>2</em><em>0</em><em>H</em><em>z</em><em> </em><em>to</em><em> </em><em>2</em><em>0</em><em>k</em><em>H</em><em>z</em>
Answer:
The answer is a. Jumper
Explanation:
The change in the momentum is represented by the equation
Acceleration of any body is calculated by the product of the mass of the body and with the velocity the same mass is moving.
Since it is mentioned in the statement that m is the mass of the jumper then velocity will also be of the jumper to calculate the change in the momentum.
If the mass of bugle cord is taken, then its velocity will be taken for the equation.
Answer:
longer than
Explanation:
given,
time of nap = 10 min
speed of orbiting earth = 8000 m/s
c is the speed of light
using the equation of time dilation
now inserting all the values
t' = 10.001 s
on solving the above equation we will get a value greater than 10minutes.
hence, On earth time of nap measured will be longer than 10 min