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2 years ago

Please help me!

Physics

1 answer:

telo118 [61]2 years ago

3 0

Answer: No, because the atomic number shown in the symbol (Z = 15) is not the atomic number of oxygen (Z = 8)

Explanation:

When we have an atom, the number in the top left is the mass number A, is equal to the sum between the number of neutrons and protons in the atom.

In this case, between protons and neutrons, we have 32.

The number at the bottom left is the atomic number Z, which is equal to the number of protons in the atom.

Particularly, this number is different for every element. For example, for the oxygen we would have Z = 8, this means that the oxygen has 8 protons.

In the image, we can see Z = 15, then the atom has 15 protons, this means that it can not be oxygen (Z = 15 is for phosphorus, then this atom would be phosphorrs). Then the symbol can not be used, because that is not oxygen.

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Do all objects have inertia <br><br> a) true<br> b) false

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The answer is A. Which is true

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2 years ago

What force, in newtons, must you exert on the balloon with your hands to create a gauge pressure of 62.5 cm H2O, if you squeeze

yulyashka [42]

Answer:54.70 N

Explanation:

Given

Gauge Pressure of $62.5 cm of H_2O$

i.e. $h=62.5 cm =0.625 m$

Effective area $A=51 cm^2$

initial Pressure $= 1 atm=101.325 kPa$

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$\rho =density\ of\ water =1000 kg/m^3$

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$P_1=\frac{F}{A}$

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$\frac{F}{A}=5.937 kPa$

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2 years ago

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1 year ago

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2 years ago

The angle between the two force of magnitude 20N and 15N is 60 degrees (20N force being horizontal) determine the resultant in m

BARSIC [14]

A) The resultant force is 30.4 N at $25.3^{\circ}$

B) The resultant force is 18.7 N at $43.9^{\circ}$

Explanation:

In order to find the resultant of the two forces, we must resolve each force along the x- and y- direction, and then add the components along each direction to find the components of the resultant.

The two forces are:

$F_1 = 20 N$ at $0^{\circ}$ above x-axis

$F_2 = 15 N$ at $60^{\circ}$ above y-axis

Resolving each force:

$F_{1x}=F_1 cos \theta = (20)(cos 0)=20 N\\F_{1y}=F_1 sin \theta =(20)(sin 0)=0 N$

$F_{2x}=F_2 cos \theta = (15)(cos 60)=7.5 N\\F_{2y}=F_2 sin \theta =(15)(sin 60)=13.0 N$

So, the components of the resultant are:

$F_x = F_{1x}+F_{2x}=20+7.5 = 27.5 N\\F_y = F_{1y}+F_{2y}=0+13.0=13.0 N$

And the magnitude of the resultant is:

$F=\sqrt{F_x^2+F_y^2}=\sqrt{27.5^2+13.0^2}=30.4 N$

And the direction is:

$\theta=tan^{-1}(\frac{F_y}{F_x})=tan^{-1}(\frac{13.0}{27.5})=25.3^{\circ}$

In this case, the 15 N is applied in the opposite direction to the 20 N force. Therefore we need to re-calculate its components, keeping in mind that the angle of the 15 N force this time is

$\theta=180^{\circ}-60^{\circ}=120^{\circ}$