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Alja [10]
2 years ago
13

Please help me!

Physics
1 answer:
telo118 [61]2 years ago
3 0

Answer: No, because the atomic number shown in the symbol (Z = 15) is not the atomic number of oxygen (Z = 8)

Explanation:

When we have an atom, the number in the top left is the mass number A, is equal to the sum between the number of neutrons and protons in the atom.

In this case, between protons and neutrons, we have 32.

The number at the bottom left is the atomic number Z, which is equal to the number of protons in the atom.

Particularly, this number is different for every element. For example, for the oxygen we would have Z = 8, this means that the oxygen has 8 protons.

In the image, we can see Z = 15, then the atom has 15 protons, this means that it can not be oxygen (Z = 15 is for phosphorus, then this atom would be phosphorrs). Then the symbol can not be used, because that is not oxygen.

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Answer:

5.0 m/s

Explanation:

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v_x = u cos \theta

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d=v_x t = (ucos \theta)t

where d = 1.95 m and t is the time needed to reach the final point.

Re-arranging for t,

t=\frac{d}{v_x}=\frac{d}{u cos \theta} (1)

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y=h+u_y t -\frac{1}{2}gt^2

where:

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h = 0 is the initial height

u_y = u sin \theta is the vertical component of the initial velocity of the salmon

g=9.81 m/s^2 is the acceleration of gravity

t is the time

Substituting t as found in eq.(1), we get the equation

y=(u sin \theta) \frac{d}{u cos \theta}- \frac{1}{2}g\frac{d^2}{u^2 cos^2 \theta}=d tan \theta - \frac{1}{2}g\frac{d^2}{u^2 cos^2 \theta}

and we can solve this formula for u, the initial speed of the salmon:

y=d tan \theta - \frac{1}{2}g\frac{d^2}{u^2 cos^2 \theta}\\\\u=\sqrt{\frac{gd^2}{2(dtan \theta -y)cos^2 \theta}}=\sqrt{\frac{(9.81)(1.95)^2}{2((1.95)(tan 37.7^{\circ}) -0.311)cos^2 37.7^{\circ}}}=5.0 m/s

5 0
3 years ago
A 2.30-kg cylindrical rod of length 2.00 m is suspended from a horizontal bar so it is free to swing about that end. a solid sph
Marina86 [1]

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h = L(1 - cosΘ) → where here L is the distance to the CM 
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Answer:

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5 0
2 years ago
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