All categories

3 years ago

Find the measure of angle 6

Mathematics

1 answer:

Serjik [45]3 years ago

6 0

Answer:

Step-by-step explanation:

<em>∠2 and ∠3 are vertical angles, => ∠2 = ∠3 = 78°.</em>

<em>∠2 and ∠6 are corresponding angles, => ∠6 = 78°.</em>

You might be interested in

Type the correct answer in the box

garri49 [273]

Answer:

26.2

Step-by-step explanation:

gooooooogle

6 0

3 years ago

Read 2 more answers

A line goes through the points (9,8) and (-6,3). What is its slope?

katovenus [111]

<h3>♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫</h3>

➷ slope = (y2 - y1)/(x2 - x1)

Substitute in the values

slope = (3-8)/(-6-9)

Solve:

slope = 1/3

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

6 0

4 years ago

Read 2 more answers

What is the x- coordinate of the zero of the graphed line?

topjm [15]

Answer:

Step-by-step explanation:

8 0

3 years ago

Can anyone teach me how to do this??

charle [14.2K]

Answer is 2 your welcome

6 0

3 years ago

State the vertical asymptote of the rational function. f(x) =((x-9)(x+7))/(x^2-4)

Lubov Fominskaja [6]

$D:x^2-4\not=0\\
D:x^2\not=4\\
D:x\not=-2 \wedge x\not =2\\\\
\displaystyle
\lim_{x\to-2^-}\dfrac{(x-9)(x+7)}{x^2-4}=\\
\dfrac{(-2-9)(-2+7)}{(-2^-)^2-4}=\dfrac{-11\cdot5}{4^+-4}=\dfrac{-55}{0^+}=-55\cdot\infty=-\infty\\
\dfrac{(-2-9)(-2+7)}{(-2^+)^2-4}=\dfrac{-11\cdot5}{4^--4}=\dfrac{-55}{0^-}=-55\cdot(-\infty)=\infty
$

$\displaystyle
\lim_{x\to2^-}\dfrac{(x-9)(x+7)}{x^2-4}=\\
\dfrac{(2-9)(2+7)}{(2^-)^2-4}=\dfrac{-7\cdot9}{4^--4}=\dfrac{-63}{0^-}=-63\cdot(-\infty)=\infty\\
\dfrac{(2-9)(2+7)}{(2^+)^2-4}=\dfrac{-7\cdot9}{4^+-4}=\dfrac{-63}{0^+}=-63\cdot\infty=-\infty\\$

So, the vertical asymptotes are $x=\pm 2$

5 0

4 years ago

Read 2 more answers