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3 years ago

PLEASE HELP!!! I don't get how to do this.

Mathematics

1 answer:

Assoli18 [71]3 years ago

6 0

1. Input:1, output:4
2. Input:1, output:6
3. Input:5, output:8
3. Input:5, output:10
The different between the inputs and outputs are 3, 5, 3, 5. See the pattern?
Hope this helped.

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Can someone tell me what 5/6 x 9/10 is and explain it please don’t just give me a answer

nadezda [96]

How this is solved is by

Multiply 5/6 with 9/10
This multiplication involving fractions can also be rephrased as "What is 5/6 of 9/10?"

5
6
×
9
10
is
3
4
.

Steps for multiplying fractions

Simply multiply the numerators and denominators separately:
5
6
×
9
10
=
5 × 9
6 × 10
=
45
60
After reducing the fraction, the answer is
3
4
Or 3/4

8 0

3 years ago

Which lines are perpendicular to 7x-3y=18

inna [77]

The answer is going to be 3y=7x-15. hope that helped

8 0

3 years ago

Classify is the function as increasing decreasing or constant l

timama [110]

Answer:

Increasing

Step-by-step explanation:

Remember that f(x) is the same as y in slope intercept form y = mx + b.

We don’t have a number for “b” which means the line goes across the origin.

Since 5 replaces m, that is the slope and since it’s positive, it is increasing.

Best of Luck!

5 0

3 years ago

Given the general form of the sinusoidal function, y = AsinB(x - C) + D, match the following items.

Jet001 [13]

Answer:

$\Delta y = A$ (Amplitude) (Correct answer: 1)

$\omega = B$ (Angular frequency) (Correct answer: 2)

$x_{o} = C$ (Phase shift) (Correct answer: 3)

$y_{o} = D$ (Vertical shift) (Correct answer: 4)

$\frac{2\pi}{\omega} = \frac{2\pi}{B}$ (Period) (Correct answer: 5)

Step-by-step explanation:

The general form of a sinusoidal function is represented by the following characteristics:

$y = \Delta y \cdot \sin \omega\cdot (x- x_{o}) + y_{o}$ (1)

Where:

$\Delta y$ - Amplitude.

$\omega$ - Angular frequency.

$x_{o}$ - Phase shift.

$y_{o}$ - Vertical shift.

$x$ - Independent variable.

$y$ - Dependent variable.

In addition, we know that the period associated with the sinusoidal function ( $T$ ) is:

$T = \frac{2\pi}{\omega}$

By direct comparison, we get the following conclusions:

$\Delta y = A$ (Amplitude) (Correct answer: 1)

$\omega = B$ (Angular frequency) (Correct answer: 2)

$x_{o} = C$ (Phase shift) (Correct answer: 3)

$y_{o} = D$ (Vertical shift) (Correct answer: 4)

$\frac{2\pi}{\omega} = \frac{2\pi}{B}$ (Period) (Correct answer: 5)

6 0

3 years ago

1) Given: circle k(O), ED= diameter ,m∠OEF=32°, m(arc)EF=(2x+10)° Find: x

qaws [65]

1. The major arc ED has measure 180 degrees since ED is a diameter of the circle. The measure of arc EF is $(2x+10)^\circ$ , so the measure of arc DF is

$m\widehat{DF}=360^\circ-180^\circ-(2x+10)^\circ=(170-2x)^\circ$

The inscribed angle theorem tells us that the central angle subtended by arc DF, $\angle DOF$ , has a measure of twice the measure of the inscribed angle DEF (which is the same angle OEF) so

$m\angle DOF=2m\angle OEF=64^\circ$

so the measure of arc DF is also 64 degrees. So we have

$170-2x=64\implies106=2x\implies\boxed{x=53}$

###

2. Arc FE and angle EOF have the same measure, 56 degrees. By the inscribed angle theorem,

$m\angle EOF=2m\angle EDF\implies56^\circ=2m\angle EDF\implies m\angle EDF=28^\circ$

Triangle DEF is isosceles because FD and ED have the same length, so angles EFD and DEF are congruent. Also, the sum of the interior angles of any triangle is 180 degrees. It follows that

$m\angle EFD+m\angle EDF+m\angle DEF=180^\circ\implies\boxed{m\angle EFD=76^\circ}$

Triangle OFE is also isosceles, so angles EFO and FEO are congruent. So we have

$m\angle EFO+m\angle FEO+m\angle EOF=180^\circ\implies\boxed{m\angle EFO=62^\circ}$

7 0

3 years ago