We are looking for the hypotenuse in this right triangle. The reference angle is 41 degrees. We have that angle and the side that is opposite that angle, 22, so the trig identity that we will use that relates the side opposite to the hypotenuse is sin. Our ratio would be set up like this: $sin(41)= \frac{22}{xy}$ . Solving for xy we will have $xy= \frac{22}{sin(41)}$ , choice D from above.

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3 years ago

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Give the domain and range a. Domain: {-3, 0, 2}, range: {3, 0, -2} b.

vlabodo [156]

Each point (x, y) is also (domain, range), so the x-values are the domain and the y-values are the range. This answer is A

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3 years ago

X^3+512=0 real or imaginary solution by factoring

Alja [10]

I hope this helps you x^3= -8^3 x= -8

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3 years ago