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Vera_Pavlovna [14]
3 years ago
8

Help me please I’m struggling to much

Mathematics
1 answer:
forsale [732]3 years ago
6 0

Answer:

\frac{16}{5} or 3.2

Step-by-step explanation:

The given triangles are similar, meaning that their corresponding sides are proportional.

The length of DC (I think its D) is 15 and the length of WZ is 3. ZY is in the same place as CE (16). Make a proportional relationship where Δ→Δ:

\frac{large}{small} =\frac{large}{small}

\frac{DC}{WZ}=\frac{CE}{ZY}

Insert the known values:

\frac{15}{3}=\frac{16}{x}

x is the value of ZY. Solve by cross multiplying:

15(x)=3(16)\\\\15x=48

Divide both sides by 15:

\frac{15x}{15} =\frac{48}{15} \\\\x=3.2

ZY is 3.2.

:Done

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C is (half of B)².
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Answer:

a) \bar{x}=4.63 md=4.55 mo= 1.9 b) Sample Standard Deviation≈ 2.58 Coefficient of Variation=55.72% Sample Range=6.9

Step-by-step explanation:

a)

<u>Mean</u>

a)\bar{x}=\frac{1.9+ 2.3+ 5.7+ 5.2+ 1.9+ 8.8+ 3.9+ 7.3}{8} =\frac{37}{8}=4.625=\approx 4.63

For the <u>Median</u>, we have to order the entries. So, ordering it goes:

1.9 1.9 2.3 3.9 5.2 5.7 7.3 8.8

Since we have even entries \frac{\frac{n}{2}+\frac{n}{2} +1}{2}=\frac{4th+5th}{2}=\frac{3.9+5.2}{2}=4.55

mode

The mode for this data 1.9 1.9 2.3 3.9 5.2 5.7 7.3 8.8 is 1.9

b)

<u>Sample Standard Deviation</u>

Here it is the formula to calculate it:

_{x}=\sqrt{\frac{\sum (x_{i}-\bar{x})^{2}}{n-1}}\\ S_{x}=\sqrt{\frac{46.855}{7}}\approx 2.58

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CV is the quocient between sample Standard deviation over Mean and it is used to make comparisons.

CV=\frac{S_x}{\bar{x}}*100%=\frac{2.58}{4.63} \approx 55.72%

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Hope this helps! :D

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Answer:

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