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3 years ago

If 10 crests and 10 troughs pass through a point in 5 seconds. Calculate its time period and frequency?

Physics

1 answer:

Artist 52 [7]3 years ago

4 0

Answer:

frequency = 5 /s

period = 0.5 s/

Explanation:

number of revolution = 10+10/2 = 20/2 = 10

frequency = n/t = 10/5 = 5 /s

period = t/n = 5/10 = 0.5s

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What are the differences between oceanic and continental crust

Lostsunrise [7]

Explanation:

Both oceanic crust and continental crust are less dense than the mantle, but oceanic crust is denser than continental crust. ... Because continental crust is less dense than oceanic crust it floats higher on the mantle, just like a piece of Styrofoam floats higher on water than a piece of wood does.

The continental crust is by far the older of the two types of crust.

Hope this helps you out ; )

6 0

3 years ago

Place the balloon in a bell jar. If available also add some shaving cream and fresh marshmallows. Ask the instructor for help if

irina [24]

Answer:

The balloon will collapse

Explanation:

When air is removed from the bell jar, the balloon will collapse if the internal pressure from the balloon does not balance the atmospheric pressure from the surroundings.

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3 years ago

An object's inertia is its tendency to maintain contact:

Gala2k [10]

hello! it is velocity.

i say this because, Inertia is the tendency of an object to resist changes in its state of motion. ... The state of motion of an object is defined by its velocity - the speed with a direction.

3 0

3 years ago

What is the speed of a walking person in m/s if the person travels 2000 m in 35 minutes?

iren [92.7K]

Distance = 2000m

Time = 35 minutes = 35×60 sec = 2100 sec

We know, Speed = Distance/Time

Therefore, Speed

= 2000m/2100s = 20/21 m/s

Answer: 20/21 m/s

Hope it helps! Please do comment

4 0

3 years ago

What is the (magnitude of the) centripetal acceleration (as a multiple of g=9.8~\mathrm{m/s^2}g=9.8 m/s 2 ) towards the Eart

Wittaler [7]

Answer:

The centripetal acceleration as a multiple of $g=9.8 m/s^{2}$ is $1.020x10^{-3}m/s^{2}$

Explanation:

The centripetal acceleration is defined as:

$a = \frac{v^{2}}{r}$ (1)

Where v is the velocity and r is the radius

Since the person is standing in the Earth surfaces, their velocity will be the same of the Earth. That one can be determined by means of the orbital velocity:

$v = \frac{2 \pi r}{T}$ (2)

Where r is the radius and T is the period.

For this case the person is standing at a latitude $71.9^{\circ}$ . Remember that the latitude is given from the equator. The configuration of this system is shown in the image below.

It is necessary to use the radius at the latitude given. That radius can be found by means of trigonometric.

$\cos \theta = \frac{adjacent}{hypotenuse}$

$\cos \theta = \frac{r_{71.9^{\circ}}}{r_{e}}$ (3)

Where $r_{71.9^{\circ}}$ is the radius at the latitude of $71.9^{\circ}$ and $r_{e}$ is the radius at the equator ( $6.37x10^{6}m$ ).

$r_{71.9^{\circ}}$ can be isolated from equation 3:

$r_{71.9^{\circ}} = r_{e} \cos \theta$ (4)

$r_{71.9^{\circ}} = (6.37x10^{6}m) \cos (71.9^{\circ})$

$r_{71.9^{\circ}} = 1.97x10^{6} m$

Then, equation 2 can be used

$v = \frac{2 \pi (1.97x10^{6} m)}{24h}$

Notice that the period is the time that the Earth takes to give a complete revolution (24 hours), this period will be expressed in seconds for a better representation of the velocity.

$T = 24h . \frac{3600s}{1h}$ ⇒ $84600s$