If 10 crests and 10 troughs pass through a point in 5 seconds. Calculate its time period and frequency?

Physics

1 answer:

Artist 52 [7]3 years ago

4 0

Answer:

frequency = 5 /s

period = 0.5 s/

Explanation:

number of revolution = 10+10/2 = 20/2 = 10

frequency = n/t = 10/5 = 5 /s

period = t/n = 5/10 = 0.5s

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The chemical energy of the battery was reduced in 10800J

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The first thing to take into account is that the stored energy in a battery is in Watts per second or Joules ( $W\cdot s=J$ ). It means that the battery provides a power for a certain time.

The idea is to know how much $W\cdot s$ has been consumed by the circuit.

The first step is to know the power that is consumed by the circuit. It is $P=V\cdot I$ . The problem says that the circuit consumes a current of 5.0A with a voltage of 6.0V. It means that the power consumed is:

$P=V\cdot I=(6.0V)\cdot (5.0A)=30W$

The previous value (30W) is the power that the circuit consumes.

Now, you must find the total amount of power that is consumed by the circuit in 6.0 minutes. You just have to multiply the power that the circuit consumed by the time it worked, it means, 6.0 minutes.

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