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Aleks04 [339]
3 years ago
12

If 10 crests and 10 troughs pass through a point in 5 seconds. Calculate its time period and frequency?

Physics
1 answer:
Artist 52 [7]3 years ago
4 0

Answer:

frequency = 5 /s

period = 0.5 s/

Explanation:

number of revolution = 10+10/2 = 20/2 = 10

frequency = n/t = 10/5 = 5 /s

period = t/n = 5/10 = 0.5s

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Drawing a shows a displacement vector (450.0 m along the y axis). In this x, y coordinate system the scalar components are Ax 0
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x ’= 368.61 m,  y ’= 258.11 m

Explanation:

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            y’= R sin 35

           

The modulus vector can be found using the Pythagorean theorem

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4 0
3 years ago
A 2.55 kg block starts from rest on a rough inclined plane that makes an angle of 60 degree with the horizontal. the coefficient
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W = -8.16 J

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So here when block moves down the inclined plane then the work done by friction force is given as

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F_f = 0.25 \times 12.5

F_f = 3.13 N

now work done by the friction is given as

W = -(3.13)(2.61)

W = -8.16 J

7 0
4 years ago
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