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Agata [3.3K]
3 years ago
12

How is cold front formation different from stationary front formation?

Physics
1 answer:
padilas [110]3 years ago
4 0

Answer:

A

Explanation:

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9) What would be the weight of a 59.1-kg astronaut on a planet with the same density as Earth and having twice Earth's radius?
Hunter-Best [27]
The weight of the astronaut is given by
W=mg
where m=59.1 kg is his mass and g=9.81~m/s^2 is the gravitational acceleration on Earth. 

To solve the problem, we must find the value of g on the new planet. g is given by
g= \frac{GM}{r^2}
where G is the gravitational constant, M the mass of the planet and r its radius. 
The mass of the planet can be written as
M=dV
where d is the density and V the volume.
We can assume that the planet is a sphere, therefore the volume is proportional to r^3:
V= \frac{4}{3}\pi r^3
and we can write the mass as
M= \frac{4}{3} \pi d r^3
and then, g becomes
g= \frac{GM}{r^2}= \frac{4}{3} \frac{G \pi d r^3}{r^2}= \frac{4}{3} G \pi d r
So, in the end g is proportional to the radius of the planet, r (because the density of the new planet d is the same as the Earth's one. If the radius of the new planet is twice the Earth's radius, g will be twice the value of g on Earth:
g_{new}=2g=2\cdot9.81~m/s^2=19.62~m/s^2
And since the mass of the astronaut is always the same, the weight on the new planet will be twice the weight on Earth:
W_{new}=mg_{new}=2mg=1159~N
5 0
4 years ago
A child has fallen while riding a bike. When should a bystander call 911 ?
kari74 [83]

Answer:

C Or D

Explanation:

The Child Should Get Checked On Before You Call The Police Thought,

4 0
3 years ago
Read 2 more answers
。and 。 are needed to describe a force
seraphim [82]
Magnitude and direction
8 0
3 years ago
What is the mass of a person who has a weight of 647N?<br> Will mark brainliest if u help me!!
Stels [109]

Answer: i think thats the answer

≈

40.8

kg

Explanation:

Well, assuming the boy is on Earth, then the gravitational acceleration is approximately

9.8

m/s

2

.

So, we get:

m

=

W

g

=

400

N

9.8

m/s

2

≈

40.8

kgExplanation:

7 0
3 years ago
A sailboat is traveling to the right when a gust of wind causes the boat to accelerate leftward at 2.5​​​​m​​/s2 for 4s. After t
Ber [7]

Answer:

+7.0 m/s

Explanation:

Let's take rightward as positive direction.

So in this problem we have:

a = -2.5 m/s^2 acceleration due to the wind (negative because it is leftward)

t = 4 s time interval

v = -3.0 m/s is the final velocity (negative because it is leftward)

We can use the following equation:

v = u + at

Where u is the initial velocity

We want to find u, so if we rearrange the equation we find:

u = v - at = (-3.0 m/s) - (-2.5 m/s^2)(4 s)=+7.0 m/s

and the positive sign means the initial direction was rightward.

6 0
4 years ago
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