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3241004551 [841]
3 years ago
7

Two blocks of masses m1 and m2 are connected to each other on an Atwood machine (the blocks are connected by a string going over

a light pulley with no friction in the bearing). A person holds one of the blocks with her hand. When the system is released, the heavier block moves down with an acceleration of 3.5 m/s2 and the lighter object moves up with an acceleration of the same magnitude. Suppose that the lighter block has a mass of m1 = 100 g. Determine the mass m2.

Physics
1 answer:
ddd [48]3 years ago
8 0

Answer:211.11 gm

Explanation:

Given

mass of lighter block m_1=100 gm

mass of heavier  block is m_2

acceleration of system a=3.5 m/s^2

From diagram

for lighter block

T-m_1g=m_1a

T=m_1(g+a)

For heavier Block

m_2g-T=m_2a

T=m_2(g-a)

Equating Tension T

m_1(g+a)=m_2(g-a)

m_2=m_1\cdot \frac{g+a}{g-a}

m_2=m_1\cdot \frac{9.8+3.5}{9.8-3.5}

m_2=0.1\cdot 2.11

m_2=0.2111 kg

m_2=211.11 gm

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