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pantera1 [17]
3 years ago
6

What is the equation of the line that is perpendicular to y = one-fifth x + 4 and that passes through (5,–4)?

Mathematics
1 answer:
zysi [14]3 years ago
4 0

Answer:

y= -5x + 21

Step-by-step explanation:

The equation of the line that passes through (5, -4)  and is perpendicular to line y = 1/5x + 4  is y= -5x + 21

The slope that is perpendicular to the slope 1/5x is -5x.

To find a perpendicular slope, you take the negative reciprocal. (so you change the signs (1/5x is positive so now it would be negative) and -5/1 is basically -5)

However, y = -5x + 4 does NOT pass through (5, -4)

But we still have to write the equation in slope intercept form or the equation of the line

<em>The formula for slope- intercept form is : y= mx + b</em>

<em>So we must plug in (m) which is our -5x and for y we look at the coordinates they gave us ----- (5, -4). -4 is our y. In the coordinates we also have x listed which is 5, so we all plug that in. </em>

<em>y = -5x + b (as you can see -5x is plugged in here)</em>

<em>-4 = -5x + b (as you can see -4 is plugged in here)</em>

<em>4 = -5(5) + b (as you can see 5 is plugged in here)</em>

<em />

<em>NOW WE MUST SOLVE!</em>

<em />

<h3><em>Isolate B</em></h3>

<em>-4 = -25 + b</em>

Add 25 from both sides.

<em>-4 = -25 + b</em>

+25 25

<em>----------------</em>

<em>21 = b</em>

We can now plug this into our slope intercept formula---y= mx+ b---to find the equation of the line.

<h2>Therefore, y = -5 x +21</h2>

<em />

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