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Afina-wow [57]
2 years ago
15

Two thirds of a number is 46. Find the number

Mathematics
1 answer:
zheka24 [161]2 years ago
8 0
2/3x = 46
2x = 46x3
2x= 138
x=138/2
x= 69

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4 0
3 years ago
Part A: The decimal form of the rational number 3/40 is
Gnom [1K]

\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\boxed{\begin{array}{c | }  \\ \bf{Part  \: A} & \bf \footnotesize{The \:  decimal \:  form  \: of \:  the \:  rational \:  number \:  \dfrac{3}{40} \: is \: \gray{ \normalsize{ 0.075 }}} \\  \\   \hline \\  \bf{Part  \: B}& \:  \bf \footnotesize{The \: value \: of \:  \dfrac{1}{ \sqrt[4]{(9)^{ - 2} } } \: is \: \normalsize 3    \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  } \\  \\ \hline \\ { \bf Part  \:C \: }&  \:  { \bf\footnotesize{On \:  simplifying  \:  \: (5+3 \sqrt{7} ) + (12 - 3 \sqrt{7}) \: we \: get \: \normalsize{ 17 }. \:  \:  \:  \:  \:  \:  \:  \:  }}    \\  \\ \end{array}}\end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}

\bf \underline{Answer-} \\

{ \bf{Part  \: A \:  | \:  \footnotesize{The \:  decimal \:  form  \: of \:  the \:  rational \:  number \:  \dfrac{3}{40} \: is \: \gray{ \normalsize{ 0.075 }}}}}

{ \bf{Part  \: B \:  | \:  \footnotesize{The \: value \: of \:  \dfrac{1}{ \sqrt[4]{(9)^{ - 2} } } \: is \: \normalsize 3   }}}

\bf \underline{Step \:by \:step\: Explanation-} \\

{ \sf  \:  \:  \:  \:  \:   :  \:  \:  \implies\dfrac{1}{ \sqrt[4]{(9)^{ - 2} } }}

{ \sf  \:  \:  \:  \:  \:   :  \:  \:  \implies\dfrac{1}{ \sqrt[ \cancel4]{(9)^{ \cancel{ - 2}} } }}

{ \sf  \:  \:  \:  \:  \:   :  \:  \:  \implies\dfrac{1}{ \sqrt{9^{  - 1} } }}

{ \sf  \:  \:  \:  \:  \:   :  \:  \:  \implies\dfrac{1}{  {3}^{ - 1  } }}

{ \sf  \:  \:  \:  \:  \:   :  \:  \:  \implies\dfrac{1}{   \dfrac{1}{3}  }}

{ \sf  \:  \:  \:  \:  \:   :  \:  \:  \implies3}

{ \bf Part  \:C \: } | \:  { \bf\footnotesize{On \:  simplifying  \:  \: (5+3 \sqrt{7} ) + (12 - 3 \sqrt{7}) \: we \: get \: \normalsize{ 17 }. }}

{~~~\sf ~~:~~\implies (5+3 \sqrt{7} ) + (12 - 3 \sqrt{7})}

{~~~~\sf ~:~~\implies 5+ \cancel{3 \sqrt{7}} + 12 \cancel{ - 3 \sqrt{7}}}

{~\sf ~~~~:~~\implies 17}

\underline{\rule{200pt}{2.5pt}}

8 0
2 years ago
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