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alex41 [277]
3 years ago
12

Steve climbed up Mt. McKinney to an elevation of 5000 feet above sea level. His brother, Sam, dove 150 feet below the sea level

to study shark. How many feel apart (in elevation) were Steve and Sam?
Mathematics
1 answer:
Allushta [10]3 years ago
7 0

Answer:

They would be 5,150 feet apart.

Step-by-step explanation:

5,000 + 150 = 5,150

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Solve for j: J/-2+7=-12
Anestetic [448]

Answer:

J=38

Step-by-step explanation:

Subtract 7 to both sides so J/-2=-19

Then multiply -2 to both sides to get -19 times -2

That equals to 38

6 0
2 years ago
The frequency distributions of two data sets are shown in the dot plots below.
fredd [130]

Answer:

1st, 4th and 6th statements are true.

Step-by-step explanation:

We have been given two dot-plots and we are asked to select all the true statements about given dot plots.

Let us write all the data points of both dot plots.

Data set 1:  

1, 1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 2, 2, 3, 3, 3, 4, 4, 7.

Data set 2:  

1, 1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 2, 2, 3, 3, 3, 4, 4.

1. The mean of data set 1 is greater than the mean of data set 2.

Let us find mean of both data sets.

\text{Mean of data set 1}=\frac{1+1+1+1+1+2+2+2+2+2+2+2+2+3+3+3+4+4+7}{19}

\text{Mean of data set 1}=\frac{45}{19}

\text{Mean of data set 1}=2.3684\approx 2.37  

\text{Mean of data set 2}=\frac{1+1+1+1+1+2+2+2+2+2+2+2+2+3+3+3+4+4}{18}

\text{Mean of data set 2}=\frac{38}{18}

\text{Mean of data set 2}=2.11

We can see that mean of data set 1 is greater than mean of data set 2, therefore, 1st statement is true.

2. The mean of data set 1 is equal to the mean of data set 2.

Since mean of data set 1 is greater than mean of data set 2, therefore, 2nd statement is false.

3. The median of data set 1 is greater than the median of data set 2.

Since data set 1 has 19 data points, so median of data set 1 will be value of 10th data set, that is 2.

Our data set 2 has 18 data points, so median of data set 2 will be the average of 9th and 10th data points.

\text{Median of data set 2}=\frac{2+2}{2}

\text{Median of data set 2}=\frac{4}{2}=2

Since median of data set 2 is also 2, therefore, 3rd statement is not true.

4. The median of data set 1 is equal to the median of data set 2.

Since both data set's median is 2, therefore, 4th statement is true.

5. The standard deviation of data set 1 is smaller than the standard deviation of data set 2.

Using online SD calculator we get SD of data set 1 is 1.422 and SD of data set 2 is 0.936. Since 1.422 is greater than 0.936, therefore, 5th statement is false.

6. The data sets have the same interquartile range.


Q_1\text{ of data set 1}=1

Q_3\text{ of data set 1}=3

\text{IQR of data set 1}=3-1=2

Q_1\text{ of data set 2}=1

Q_3\text{ of data set 2}=3

\text{IQR of data set 2}=3-1=2

Since both data set's IQR is 2, therefore, 6th statement is true.

3 0
3 years ago
Read 2 more answers
Evaluate the expressio <br>-6(-5)+12
natta225 [31]

First, multiply -6*-5. This equals (positive) 30 because the negative signs cancel out.

This leaves you with:

30+12

Doing the addition leaves you with 42.

The answer is 42.

I hope this helps :)

6 0
3 years ago
Read 2 more answers
Scale each ratio or rate up or down to determine the unknown term
balu736 [363]
D) 1•x=5, 1•5=5 8•5=40, the answer is 40/5 CDs

E) 3/3=1, 26.25/3= 8.75. The answer is 1/8.75

F) 10/10=1, 120/10= 12. The answer is 1/12

G) 2•x=12, 2•6=12, 120•6= 720. The answer is 12/720

Hopefully this helped
5 0
2 years ago
Malorie can work 10 math problems in 3 minutes.
Slav-nsk [51]
200
You divide 60 by 3 because there are 60 m minutes in 1 hour. You get 20. 
You then multiply 10 by 20 and you get 200. 
Hope this helps! :)
6 0
3 years ago
Read 2 more answers
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