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Maslowich
3 years ago
14

A marketing manager for a cell phone company claims that the percentage of children aged - who have cell phones differs from . I

n a survey of children aged - by a national consumers group, of them had cell phones. Can you conclude that the manager's claim is true
Mathematics
1 answer:
k0ka [10]3 years ago
3 0

Answer:

Yes, the marketing manager's claim is true.

Step-by-step explanation:

p = 0.61

Phat = 545 /826 = 0.66

H0 : p = 0.61

H1 : p ≠ 0.61

The test statistic :

(Phat - p) / √pq/n

q = 1 -p = 1 - 0.61 = 0.39

(0.66 -0.61) / √(0.61*0.39)/826

0.05 / 0.0169709

Test statistic = 2.95

Using the p-value from Zscore calculator:

Pvalue at 2.95, two tailed ;

Pvalue = 0.0032

Reject H0; if Pvalue < α

Since, Pvalue < α ; Then, the marketing manager's claim is true

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Answer:

Part 1)

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Part 2)

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Step-by-step explanation:

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Given

\overrightarrow{v_{a}}=\widehat{i}-2\widehat{j}+\widehat{k}

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\overrightarrow{v_{a}}\cdot \overrightarrow{v_{b}}=(\widehat{i}-2\widehat{j}+\widehat{k})\cdot (4\widehat{i}-4\widehat{j}+7\widehat{k})\\\\\overrightarrow{v_{a}}\cdot \overrightarrow{v_{b}}=1\cdot 4+2\cdot 4+1\cdot 7=19

Part 2)

Given vector A' as

\overrightarrow{v_{a'}}=2\widehat{i}+3\widehat{j}+6\widehat{k}

Similarly vector B' is written as

\overrightarrow{v_{b'}}=\widehat{i}+5\widehat{j}+3\widehat{k}

Thus the vector dot product of the 2 vectors is obtained as

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Answer:

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Then, the area of the triangle plus the area of the semicircle is:

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