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Svetach [21]
3 years ago
8

How to rationalize the denominator?​

Mathematics
1 answer:
VMariaS [17]3 years ago
3 0

Step-by-step explanation:

So, in order to rationalize the denominator, we need to get rid of all radicals that are in the denominator.

Step 1: Multiply numerator and denominator by a radical that will get rid of the radical in the denominator. ...

Step 2: Make sure all radicals are simplified. ...

Step 3: Simplify the fraction if needed.

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About 3% of children in the United States are allergic to peanuts. Choose three children at random and let the random variable X
Charra [1.4K]

Answer:

0.029991 = 2.9991% conditional probability that exactly two of the children will be allergic to peanuts, given that at least one of the three children suffers from this allergy

Step-by-step explanation:

For each children, there are only two possible outcomes. Either they are allergic to peanuts, or they are not. The probability of a children being allergic to peanut butter is independent of other children. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

3% of children in the United States are allergic to peanuts.

So p = 0.03

Three children:

So n = 3,

The probabilities are:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{3,0}.(0.03)^{0}.(0.97)^{3} = 0.912673

P(X = 1) = C_{3,1}.(0.03)^{1}.(0.97)^{2} = 0.084681

P(X = 2) = C_{3,2}.(0.03)^{2}.(0.97)^{1} = 0.002619

P(X = 3) = C_{3,3}.(0.03)^{3}.(0.97)^{0} = 0.000027

What is the conditional probability that exactly two of the children will be allergic to peanuts, given that at least one of the three children suffers from this allergy?

This is

p = \frac{P(X = 2)}{P(X \geq 1)}

In which

P(X \geq 1) = 0.084681 + 0.002619 + 0.000027 = 0.087327

P(X = 2) = 0.002619

So

p = \frac{0.002619}{0.087327} = 0.03

0.029991 = 2.9991% conditional probability that exactly two of the children will be allergic to peanuts, given that at least one of the three children suffers from this allergy

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Answer:

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