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Jlenok [28]
3 years ago
12

I have to plot,, y=5x-0 on this graph! can someone help?

Mathematics
1 answer:
Darina [25.2K]3 years ago
3 0

Answer:

Start from (0,0) and go up 10 for every 1 over

Step-by-step explanation:

You can disregard the 0 since it does virtually nothing, which means your y-intercept is at (0,0)

if that sounds confusing then just plug in the numbers on the bottom axis for x and they will give you the y values

for example when x is 10 (bottom axis), you would do y=5(10) so y= 50, so then you would have a point at (10,50)

and then since its a linear equation, its just a straight line so you can connect (0,0) to (10,50) and yay you have a line (since y=5(0) gives y=0)

lmk if I'm not making any sense

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2 years ago
Based on the diagram, which expresses all possible
qaws [65]

The expression that expresses all possible lengths of segment AB is 27 < AB < 81. The correct option is the second option 27 < AB < 81

<h3>Properties of a triangle</h3>

From the question, we are to determine the expression that expresses all possible lengths of segment AB

From one of the properties of a triangle,

The <u>third side</u> of any triangle is greater than the difference of the other <u>two sides</u>; and the <u>third side</u> of any triangle is lesser than the sum of the <u>two other sides</u>

Then, we can write that

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and

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Putting the two inequalities together, we get

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Hence, the expression that expresses all possible lengths of segment AB is 27 < AB < 81. The correct option is the second option 27 < AB < 81

Learn more on the Properties of a triangle here: brainly.com/question/1851668

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The question is incomplete.

The complete question is in the picture, please refer to the attached picture.

We have given two triangles:

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AS we can see Line segment RS and UV are parallel.

Which is crossed by a transversal RV.

The angle SRV = Angle RVU

Thus, the option third ∠R ≅ ∠V is correct because line segment RS and UV are parallel which is crossed by a transversal RV.

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