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slega [8]
3 years ago
12

What is the area of the shaded portion in the square?

Mathematics
1 answer:
kicyunya [14]3 years ago
4 0

Answer:

36 - 9pi

Step-by-step explanation:

Shaded part = Area of square - Area of white part

= 6^2 - (1/4)*pi*6^2 [Since, the white part is one-fourth of a circle with radius 6 units]

= 36 - 9pi

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Plssss I need help Im in classsss plsss
Sav [38]

Step-by-step explanation:

Y=-4x+3

2x+3y=19

2x+3(-4x+3)=19

2x-12x+9=19

-10x=10

X=-1

y=-4*(-1)+3=4+3=7

x=-1 y=7

5 0
3 years ago
A recycling bin is in the shape of a right rectangular prism. The bin is 12 meters long, 512 meters wide, and 612 meters tall. W
Colt1911 [192]
The volume of a rectangular prism can be found using the formula V = WHL.

W is the width, H is the height, and L is the length.

V = 512×612×12
V = 3,760,128

The volume of the bin is 3,760,128
3 0
3 years ago
Read 2 more answers
WILL GIVE A BRAINLIEST
skelet666 [1.2K]
Find slope
slope betwen 2 points (x1,y1) and (x2,y2) is (y2-y1)/(x2-x1)

so
first make denoms same
denom is 10
(4/5,1/5) turns to (8/10,2/10)
(1/2,3/2) turns to (5/10,15/10)
slope=(15/10-2/10)/(5/10-8/10)=(13/10)/(-3/10)=13/-3=-13/3

use point slope
use (4/5,1/5)
y-y1=m(x-x1)
a point is (x1,y1) and slope is m
y-1/5=-13/3(x-4/5)
expand
wait, we don't need to do that, the only one with slope -13/3 is D
answer is D
4 0
3 years ago
you have dance lessons every fifth day and you have skateboarding lessons every third day. today you have both lessons.in how ma
Neko [114]

Answer:

try to find their HCF or lcm I got the same type of question

5 0
2 years ago
Read 2 more answers
I need help learning how to solve this problem please.
Radda [10]

we have 4 gals, Stephanie, Andrea, Emily and  Becca.

btw the end point should be (-6, -7) and the start point is (8, 6).

so, if we know the distance between those two points, we can just cut it in 4 equal pieces and each gal will be driving a piece.

now, Emily's turn is after Andrea, BUT, we had first Stephenie driving ¼ of the way, then Andrea driving ¼ of the way too, but after ¼+¼, Emily comes on, but ¼+¼ is really 1/2, so when Emily starts, is really half-way through, or the midpoint of that distance.


\bf ~~~~~~~~~~~~\textit{middle point of 2 points }
\\\\
\stackrel{\textit{Hometown}}{(\stackrel{x_1}{8}~,~\stackrel{y_1}{6})}\qquad
\stackrel{\textit{San Antonio}}{(\stackrel{x_2}{-6}~,~\stackrel{y_2}{-7})}
\qquad
\left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right)
\\\\\\
\left( \cfrac{-6+8}{2}~~,~~\cfrac{-7+6}{2} \right)\implies \left(\cfrac{2}{2}~,~\cfrac{-1}{2} \right)\implies \stackrel{\textit{Emily starts off}}{\left(1~,-\frac{1}{2} \right)}


Emily's turn ends ¼ of the way later, which will be pretty much half-way in between  (1, -½) and (-6, -7), so is really the midpoint of those two.


\bf ~~~~~~~~~~~~\textit{middle point of 2 points }
\\\\
(\stackrel{x_1}{1}~,~\stackrel{y_1}{-\frac{1}{2}})\qquad
\stackrel{\textit{San Antonio}}{(\stackrel{x_2}{-6}~,~\stackrel{y_2}{-7})}
\\\\\\
\left( \cfrac{-6+1}{2}~~,~~\cfrac{-7-\frac{1}{2}}{2} \right)\implies \left( \cfrac{-5}{2}~,~\cfrac{~\frac{-14-1}{2}~}{2} \right)\implies \left( \cfrac{-5}{2}~,~\cfrac{~\frac{-15}{2}~}{2} \right)
\\\\\\
\left( \cfrac{-5}{2}~,~\cfrac{-15}{4} \right)\implies \left( -2\frac{1}{2}~,~-3\frac{3}{4} \right)

8 0
3 years ago
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