ANSWER 9:
The offset address of an element in row 16 and column 3 = 0100000011 (10 bits address)
Explanation:
The size of bit fields for row and column numbers should be big enough to accommodate the highest possible row and column numbers.
For 57 × 10 matrix M will have 6 bits for rows (26=64 so 6 bits can accommodate 57 values) and 4 bits for columns (24 =16 so 4 bits can accommodate 10 values). For offset address of an element in row 16 and column 3:
6 bits of row address will be the binary value of 16 = 010000
4 bits of column address will be the binary value of 3 = 0011
Now, for offset address of an element in row 16 and column 3 will be the concatenation of row and column address = 010000 concat 0011 = 0100000011 (10 bits address)
Four binary digits
A single hexadecimal digit can represent four binary digits.
Answer:
D) Black -hat
Explanation:
if any other colors of the hats will not work cuz the only way to go dark and scary is to use the black hat
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