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Mandarinka [93]
3 years ago
15

QUICK HURRY PLEASE Liam gave his friends a puzzle. He said he had two numbers that were not between -1 and 1. However, when the

Mathematics
2 answers:
egoroff_w [7]3 years ago
6 0

Answer:

D

Step-by-step explanation:

One number will be positive, and one will be negative

kompoz [17]3 years ago
3 0

Answer:

The answer is option D

Step-by-step explanation:

multiplication of numbers having opposite signs will result in a number having negative sign .

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The drama club is having a car wash as a fundraiser. They wash x cars at $5 each
Galina-37 [17]

<u>Answer:</u>

x + y ≥ 26 + 15

5x + 8y ≥ 250 (see below)

Step-by-step explanation:

First, write an equation to represent the total cost to wash cars:

$5x = cost for cars

Then, write another for trucks:

$8y = cost for trucks

If the question is saying that they will wash at least 26 cars and 15 trucks, that means they could wash more. This means that we'll need an inequality:

This inequality represents that the total number of cars and trucks they wash will be at least—which means that it is equal to or greater than—than the amount given:

x + y ≥ 26 + 15

Any equation or inequality with two unknowns is not solvable, meaning we need a system of equations:

If they make at least $250, that means that we need to combine the costs of the cars and trucks to make an inequality:

5x + 8y ≥ 250

Now you have your system of equations:

x + y ≥ 26 + 15

5x + 8y ≥ 250

8 0
3 years ago
What are the like terms in the expression 8+x²-4x³+5x+2x²​
Virty [35]
X^2 and 2x^2 are alike.
They both have variables and the same exponent
4 0
3 years ago
MATH HELP PLEASE!!! PLEASE HELP!!!
grandymaker [24]
The answer is:  [C]:  " f(c) = \frac{9}{5} c  + 32 " .
________________________________________________________

Explanation:

________________________________________________________
Given the original function:  

" c(y) = (5/9) (x <span>− 32) " ; in which "x = f" ; and "y = c(f) " ;
________________________________________________________
</span>→  <span>Write the original function as:  " y = </span>(5/9) (x − 32) " ; 

Now, change the "y" to an "x" ; and the "x" to a "y"; and rewrite; as follows:
________________________________________________________
    x = (5/9) (y − 32) ; 

Now, rewrite THIS equation; by solving for "y" ; in terms of "x" ; 
_____________________________________________________
→ That is, solve this equation for "y" ; with "c" as an "isolated variable" on the
 "left-hand side" of the equation:

We have:

→  x  =  " (  \frac{5}{9}  ) * (y − 32) " ;

Let us simplify the "right-hand side" of the equation:
_____________________________________________________

Note the "distributive property" of multiplication:
__________________________________________
a(b + c) = ab + ac ;  <u><em>AND</em></u>:

a(b – c) = ab – ac
.
__________________________________________

As such:
__________________________________________

" (\frac{5}{9}) * (y − 32) " ; 

=  [ (\frac{5}{9}) * y ]   −  [ (\frac{5}{9}) * (32) ] ; 


=  [ (\frac{5}{9}) y ]  − [ (\frac{5}{9}) * (\frac{32}{1})" ;

=  [ (\frac{5}{9}) y ]  − [ (\frac{(5*32)}{(9*1)} ] ; 

=  [ (\frac{5}{9}) y ]  −  [ (\frac{(160)}{(9)} ] ; 

= [ (\frac{5y}{9}) ]  −  [ (\frac{(160)}{(9)} ] ; 

= [ \frac{(5y-160)}{9} ] ;  
_______________________________________________
And rewrite as:  

→  " x  =  \frac{(5y-160)}{9} "  ;

We want to rewrite this; solving for "y";  with "y" isolated as a "single variable" on the "left-hand side" of the equation ;

We have:

→  " x  =  \frac{(5y-160)}{9} "  ; 

↔  " \frac{(5y-160)}{9} = x ; 

Multiply both sides of the equation by "9" ; 

 9 * \frac{(5y-160)}{9}  =  x * 9 ; 

to get:

→  5y − 160 = 9x ; 

Now, add "160" to each side of the equation; as follows:
_______________________________________________________

→  5y − 160 + 160 = 9x + 160 ; 

to get:

→  5y  =  9x + 160 ; 

Now,  divided Each side of the equation by "5" ; 
      to isolate "y" on one side of the equation; & to solve for "y" ; 

→  5y / 5  = (9y + 160) / 5 ; 

to get: 
 
→  y = (9/5)x + (160/5) ; 

→  y =  (9/5)x + 32 ; 

 →  Now, remember we had substituted:  "y" for "c(f)" ; 

Now that we have the "equation for the inverse" ;
     →  which is:  " (9/5)x  + 32" ; 

Remember that for the original ("non-inverse" equation);  "y" was used in place of "c(f)" .  We have the "inverse equation";  so we can denote this "inverse function" ; that is, the "inverse" of "c(f)" as:  "f(c)" .

Note that "x = c" ; 
_____________________________________________________
So, the inverse function is: "  f(c) = (9/5) c  + 32 " .
_____________________________________________________

 The answer is:  " f(c) = \frac{9}{5} c  + 32 " ;
_____________________________________________________
 →  which is:  

→  Answer choice:  [C]:  " f(c) = \frac{9}{5} c  + 32 " .
_____________________________________________________
6 0
3 years ago
If the measure of arc GH = 110 and the measure of arc EF =55 calculate m angleGDH
natulia [17]
If I remember My geometry correctly
you add GH AND EF then divide 2
3 0
3 years ago
Read 2 more answers
Help please. math isn't my strong suit.
Neporo4naja [7]
What are you needing help with 

6 0
3 years ago
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