Answer:
Part A: (1/2)m
Part B: (1/3rd)b and 3mx
Step-by-step explanation:
Price of each baseball is=$m
Price of other equipment are=$b collectively
Total amount He spent on purchasing equipment is =(m+b)$
Part A:
in part A the amount on purchasing other equipment than baseball is getting doubled i.e. $2b <u> then value of m will be (1/2)half of the total amount spent on purchasing baseball i.e. (1/2)m</u>
Part B:
in part B the amount spent on purchasing baseball is getting tripled i.e. <u>3m</u>, then value of b(amount of purchasing other equipment) is<u> (1/3rd) of total</u> <u>amount spent on purchasing other equipment</u> and value of mx will be<u> 3mx</u>
Answer:
Step-by-step explanation:
2^-3=1/2^3
3^-2=1/3^2
(2^-3)(3^-2)=1/72
Answer:
1.1
Step-by-step explanation:
1 in probability means always so anything greater than 1 is meaningless
Answer:
![\frac{3}{7}](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B7%7D)
Step-by-step explanation:
Start by finding how many integers there are from 10-30...
30-10+1=20+1=21
Note we have to add 1 since it is inclusive.
Now, let's find how many multiples of 4 or 5 there are from 10-30...
4*3=12
4*4=16
4*5=20
4*6=24
4*7=28
5*2=10
5*3=15
5*4=20
5*5=25
5*6=30
5+5-1=9
Note we have to subtract 1 since 20 is counted twice.
The probability would be...
![\frac{Multiples\ of\ four\ and\ five\ from\ 10-30}{Amount\ of\ integers\ between\ 10-30}=\frac{9}{21}=\frac{3}{7}](https://tex.z-dn.net/?f=%5Cfrac%7BMultiples%5C%20of%5C%20four%5C%20and%5C%20five%5C%20from%5C%2010-30%7D%7BAmount%5C%20of%5C%20integers%5C%20between%5C%2010-30%7D%3D%5Cfrac%7B9%7D%7B21%7D%3D%5Cfrac%7B3%7D%7B7%7D)
Answer:
x = 3 ± ![\sqrt{13}](https://tex.z-dn.net/?f=%5Csqrt%7B13%7D)
Step-by-step explanation:
x² - 6x - 4 = 0 ( add 4 to both sides )
x² - 6x = 4
To complete the square
add ( half the coefficient of the x- term)² to both sides
x² + 2(- 3)x + 9 = 4 + 9
(x - 3)² = 13 ( take square root of both sides )
x - 3 = ±
( add 3 to both sides )
x = 3 ± ![\sqrt{13}](https://tex.z-dn.net/?f=%5Csqrt%7B13%7D)