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victus00 [196]
3 years ago
6

Use logarithmic differentiation to find the derivative with respect to x of the function y= (sin x)^lnx

Mathematics
1 answer:
Helga [31]3 years ago
4 0
Logarithmic differentiation means tAke logarithm of both sides to make the function easier to find the derivative.

y = (sinx)^lnx

ln(y) = ln((sinx)^lnx)

power rule logarithm

ln(y) = ln(x) ln(sinx)

Take derivative

y'/y = ln(sinx)(1/x) + ln(x) cosx/sinx

multiply both sides by y

y' = y( ln(sinx)/x + ln(x)cotx )

remember y = (sinx)^lnx
sub this in for y

y' = (ln(sinx)/x + ln(x)cotx)(sinx)^lnx
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This is your answer
7 0
4 years ago
Read 2 more answers
I need help with 2b.
kodGreya [7K]

Answer:

The answer to your question

a) Values excluded = -2, 0

b) solutions = -2/3, 2

Step-by-step explanation:

Equation

                        \frac{4x}{2x + 4} = \frac{x+ 2}{2x}

a) x is restricted when the denominators equal zero, so let's get them.

                 2x + 4 = 0                           2x =  0

                 2x = - 4                                  x = 0 / 2

                 x = -4 / 2                               x = 0

                 x = -2

x must be different to -2, 0

b)                   \frac{4x}{2x + 4} = \frac{x+ 2}{2x}

                      \frac{2x}{x + 2} = \frac{x + 2}{2x}

                      4x² = (x + 2)²

                      4x² = x² + 4x + 4

                     4x² - x² - 4x - 4 = 0

                      3x² - 4x - 4 = 0

                      3x² - 6x + 2x - 4 = 0

                     3x(x - 2) + 2(x - 2) = 0

                     (x - 2)(3x + 2) = 0

                      x₁ - 2 = 0                  3x₂ + 2 = 0

                     x₁ = 2                         x₂ = -2/3

                             

7 0
3 years ago
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