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victus00 [196]
3 years ago
6

Use logarithmic differentiation to find the derivative with respect to x of the function y= (sin x)^lnx

Mathematics
1 answer:
Helga [31]3 years ago
4 0
Logarithmic differentiation means tAke logarithm of both sides to make the function easier to find the derivative.

y = (sinx)^lnx

ln(y) = ln((sinx)^lnx)

power rule logarithm

ln(y) = ln(x) ln(sinx)

Take derivative

y'/y = ln(sinx)(1/x) + ln(x) cosx/sinx

multiply both sides by y

y' = y( ln(sinx)/x + ln(x)cotx )

remember y = (sinx)^lnx
sub this in for y

y' = (ln(sinx)/x + ln(x)cotx)(sinx)^lnx
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After heating a fixed volume of gas at 50 psia from 300° R to 600°R, its pressure will be:
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100 psia

Step-by-step explanation:

Applying,

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P/T = P'/T'................. Equation 1

Where P = initial pressure, P' = Final pressure, T = initial temperature, P' = Final temperature.

make P' the subject of the equation

P' = PT'/T............ Equation 2

From the question,

Given: P = 50 psia, T = 300°R = (300×5/9)K = 166.66 K, T' = 600°R = (600×5/9)K = 333.33 K

Substitute these values into equation 2

P' = (50×333.33)/166.66

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