If the negative square root is found to be one of your solutions, then that is indicative of a pair of imaginary roots (the imaginary i). According to the conjugate rule, if you have one solution that is imaginary, you will have another but with the opposite sign. For example, if a solution to a quadratic is found to be 2 - i, then its conjugate, 2 + i is also a solution. They will ALWAYS go in pairs. Same thing with radical solutions. If one solution is found to be 
then 
will also be a solution.
Lmbo
you do flvs too the answers B
Answer:2/pi
Step-by-step explanation:
First, name the points. Top Left will be A, Top Right will be B, Bottom Right will be C, and Bottom Left will be D. Now, the area of ABCD is 4. Then, we have to find the area of the circle. The center to the midpoint of AB is 1. The length of the midpoint of AB to B is 1. So, using the Pythagorean Theorem, it will be 1^2 + 1^2 = 2, then it will be sqrt2. Finding the area of the circle will be easy now that we have the radius. sqrt2*sqrt2*pi = 2pi. So, it will be 4/2pi, and simplified, it will be 2/pi.
Answer:
A
Step-by-step explanation:
sorry if its wrong
Answer:
(x)2+(y)2=625
Step-by-step explanation:
