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MakcuM [25]
3 years ago
9

PLEASE HELPP I NEED TO GET A GOOD GRADE :(((((((((((((((9

Mathematics
1 answer:
leva [86]3 years ago
4 0

Answer:

circumference = 2 π r

perimeter = 41.1 ,

Step-by-step explanation:

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Order 0.5 , 0.66 , -1.5 , -1.25 from least to greatest
fenix001 [56]

Answer:

-1.25, -1.5, 0.5, 0.66

hope it helps you

7 0
4 years ago
Solve the following inequality<br> 23x +1 &gt; -45
Alenkasestr [34]

Answer:

-2

Step-by-step explanation:

23x + 1 > - 45

or, 23x > - 45 - 1

or, 23x > - 46

or, x > - 46/23

or, x > - 2

hope it will help you☺

7 0
3 years ago
60<br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B60%7D%7B108%3F%7D%20" id="TexFormula1" title=" \frac{60}{108?} " alt=" \fra
Phantasy [73]

I guess you want to simplify this:-

60 / 108   = 30/54      (dividing top and bottom by 2)

= 15/27   ( divide by 2 again)

= 5/9   Answer    (dividing   top and bottom by 3)

6 0
3 years ago
Read 2 more answers
GIVING BRAINLIESST PPL
GrogVix [38]
You need to split the shape into simpler shapes so you would get a rectangular prism and a triangular prism finding the volume is pretty straightforward the formula is

Volume of a triangular prism = area of base triangle × height

The formula for finding the volume of a rectangular prism is the following: Volume = Length * Height * Width, or V = L * H * W.
After solving for this you would just have to add the 2 shapes volume together tie get the volume of the composite figure
Finding the surface area is also pretty simple since it would only require you to know the formulas

S = 2(lw + lh + wh) to find the surface area of a rectangle or prism

A=12bh is used to find the area of the top and bases triangular faces, where A = area, b = base, and h = height.
And by adding the two surface areas of the shapes you can get the surface area of the composite figure but remember to subtract the top face of the rectangular prism and the bottom face of the triangular prism
Hope this helps <3
4 0
3 years ago
Which expression is equivalent to (2^3)^-5
34kurt
\text{Use:}\\\\(a^n)^m=a^{nm}\\\\a^{-n}=\dfrac{1}{a^n}\\\\\left(2^3\right)^{-5}=2^{3\cdot(-5)}=2^{-15}=\dfrac{1}{2^{15}}
6 0
4 years ago
Read 2 more answers
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