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bearhunter [10]
3 years ago
15

I need help asap, I will report any links or files from bit. ly

Mathematics
1 answer:
Vilka [71]3 years ago
8 0

Answer:

I think the answer for that question is c

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D
kirza4 [7]

Answer:

12+k/5

Quotient is a quantity produced by the division of two numbers.

8 0
3 years ago
A rectangle initially has width 7 meters and length 10 meters and is expanding so that the area increases at a rate of 8 square
Tems11 [23]

Answer:

The length of rectangular is increasing at a rate 0.5714 meters per hour.

Step-by-step explanation:

We are given the following in the question:

Initial dimensions of rectangular box:

Length,l = 10 m

Width,w = 7 m

\dfrac{dA}{dt} = 8\text{ square meters per hour}\\\\\dfrac{dw}{dt} = 40\text{ centimeters per hour} =0.4\text{ meters per hour}

We have to find the rate of increase of length.

Area of rectangle =

A = l\times w

Differentiating we get,

\displaystyle\frac{dA}{dt} = \frac{dl}{dt}w + \frac{dw}{dt}l

Putting values, we get,

8 = \dfrac{dl}{dt}(7) + (0.4)(10)\\\\\dfrac{dl}{dt}(7) = 8 -4\\\\\dfrac{dl}{dt} \approx 0.5714

Thus, the length of rectangular is increasing at a rate 0.5714 meters per hour.

5 0
3 years ago
Identify the GCF of 6x^2y^2 − 8xy^2 + 10xy
myrzilka [38]

Answer:

The GCF for the numerical part is 2

Step-by-step explanation:

6x^2y^2-8xy^2+10xy

It contains both numbers and variables, there are two steps to find the GCF(HCF).

1). Find the GCF for the numerical part 6, -8,10

2). Find the GCF for the variable part x^2,y^2,x^1,y^2,x^1,y^3

3).Multiply the values together.

Find the common factors for the numerical part:

6,-8,10

Factors of 6

6: 1,2,3,6

Factors of -8

-8: -8,-4,-2,-1,1,2,4,8

Factors of 10

10:1,2,5,10

Common factors of 6,-8, 10 are 1,2

The GCF Numerical=2

The GCF Variable= xy^2

Multiply the GCF of the numerical part 2 and the GCF of the variable part xy^2, and you'll get 2xy^2

6 0
2 years ago
I GIVR BRAINLIST AND POINTS
PIT_PIT [208]

Answer:

d

Step-by-step explanation:

4 0
3 years ago
The water level in a lake was 22 inches below normal at the beginning of March. The water level decreased by 3 1/6 inches in Mar
Vinvika [58]
At the beginning it was 22 inches below normal (-22).
Then it decreased by 3 1/6 (-19/6).
Then increased by 1 6/7 (+13/7)

-22 - 19/6 + 13/7
-924/42 - 133/42 + 78/42
-1057/42 + 78/42
-979/42
-23 13/42

It was 23 13/42 inches below normal after April.
8 0
3 years ago
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