Answer:
a) 
b) 
Explanation:
Given:
Mass of the cabinet, m = 51 kg
a) Applied force = 200 N
Now the force required to move the from the state of rest (F) = coefficient of static friction (
)× Normal reaction(N)
N = mg
where, g = acceleration due to gravity
⇒N = 51 kg × 9.8 m/s²
⇒N = 499.8 N
thus, 200N =
× 499.8 N
⇒
= 
b) Applied force = 100 N
since the cabinet is moving, thus the coefficient of kinetic(
) friction will come into action
Now the force required to move the from the state of rest (F) = coefficient of kinetic friction (
)× Normal reaction(N)
N = mg
where, g = acceleration due to gravity
⇒N = 51 kg × 9.8 m/s²
⇒N = 499.8 N
thus, 100N =
× 499.8 N
⇒
= 
<u>Answer:</u> 3
H = 45 m ,
time required for the stone
S = u.t+(1/2) g.t²
45 = (1/2) 9.81. t² since u( initial velocity) = 0 ; S =H.
t² = 9.17 s
<em> t = 3.02 s </em>
therefore answer is 3 m/s
<em> if you satisfy with explanation, please give brainiest ; </em>