someone help pls. Two students, Mia and Peter, leave school to meet at the local coffee shop. Peter decides to jog to the coffee
shop, but also stops at a flower shop along the way. Mia decides to walk from school directly to the coffee shop. They arrive at the coffee shop at the same time, 30 minutes after they leave school.
1 answer:
Answer:
1) The distance further it takes Peter to arrive at the Coffee shop than Mia is 1.24 km
2) Mia's average speed is 6.00 km/hour
Peter's average speed is 8.48 km/hour
4) Mia's average velocity = Peter's average velocity = 6.00 km/hour
Explanation:
The given information from the diagram are;
The distance Peter jogs from school to the flower shop = 2.00 km
The distance Peter jogs from the Flower shop to the Coffee shop = 2.24 km.
The distance Mia walks from school directly to the Coffee shop = 3.00 km
The time it takes both Peter and Mia to arrive at the coffee shop = 30 minutes = 0.5 hour
1) The total distance Peter travels from school to the Coffee shop = 2.00 km + 2.24 km = 4.24 km
The distance Mia travels from school to the Coffee shop = 3.00 km
The distance further it takes Peter to arrive at the Coffee shop than Mia = 4.24 km - 3.00 km = 1.24 km
The distance further it takes Peter to arrive at the Coffee shop than Mia = 1.24 km
2)
Mia's average speed = 6.00 km/hour
Peter's average speed = 8.48 km/hour
4)
The displacement from the School to the Coffee shop is 3.00 km for both Mia and Peter
The time it takes both Peter and Mia to arrive at the Coffee shop from the school is 30 minutes = 0.5 hour
Mia's average velocity = 6.00 km/hour
Therefore, Peter's average velocity is also = 6.00 km/hour
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Put all the values in above formula we get,
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T = 1065.6 N
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