The answer is D. the way I remember it is they all end with -alism.
Answer:
W = 30 N
Explanation:
Applying the summation of torques about the wedge for equilibrium, taking the clockwise direction as negative. Since the ruler is balanced horizontally about the wedge. Therefore, the summation of all torques acting about the wedge must be equal to zero.

<u>W = 30 N</u>
Answer:
Suppose two objects of different masses are moving with different velocities in the same direction on a straght-line before collision. After collision, they stick together and move with common (the same) velocity
Answer:
19.6 m/s
Explanation:
The parameters given are:
Mass M = 20 Kg
Force F = 285 N
Angle Ø = 30 degree
Time t = 4 seconds
Coefficient of friction = 0.72
At the plane, the weight of the box will be mgsinØ
Resolving forces at the plane, we will have:
MgsinØ + Fr = F
Where Fr = frictional force.
Fr = F - mgsinØ
Substitute all the parameters into the formula
Fr = 285 - 20 × 9.8 sin30
Fr = 285 - 98
Fr = 187 N
But for the box moving toward the top of the plane,
F - Fr = ma
Where a = V/t
Substitute all the parameters involved into the formula
285 - 187 = 20 ( V/4)
98 = 5V
V = 98/5
V = 19.6 m/s
Therefore, the speed with which the box is moving is 19.6 m/s