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Oksana_A [137]
4 years ago
8

List some of the most common injuries that can occur from sports. Please hurry!

Physics
1 answer:
vredina [299]4 years ago
5 0
ACL tear, meniscus, turf toe, bunions, concussion, broken nose, broken arm,broken ankle
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You are designing a ski jump ramp for the next Winter Olympics. You need to calculate the vertical height h from the starting ga
Evgen [1.6K]

Answer:

h = 40.37 m

Explanation:

We will apply the law of conservation of energy to the skier in this case, as follows:

Energy\ of\ skier\ at\ the\ gate = Energy\ of\ Skier\ at\ the\ end\\P.E + K.E_{i} = K.E_{f} - W_{friction}\\mgh + \frac{1}{2}mv_{i}^2 = \frac{1}{2}mv_{f}^2 - W_{friction}\\\\mgh = \frac{1}{2}m(v_{f}^2-v_{i}^2) - W_{friction}

where,

m = mass of skier = 77 kg

g = acceleration due to gravity = 9.81 m/s²

vf = final speed = 30 m/s

vi = initial speed = 2 m/s

W_friction = Work done by friction and air resistance = 4000 J

Therefore,

(77\ kg)(9.81\ m/s^2)h = \frac{1}{2}(77\ kg)[(30\ m/s)^2-(2\ m/s)^2] - 4000\ J\\\\h = \frac{34496\ J - 4000\ J}{755.37\ N}\\\\

<u>h = 40.37 m</u>

5 0
3 years ago
State the principle of floatation​
WARRIOR [948]

Explanation:

<em><u>Principle of Floatation</u></em>

Principle of Floatation states that weight of floating body is equal to weight of water displaced by it

7 0
3 years ago
Pls answer!! 20 points and will give crown to best answer!!
docker41 [41]
I am 99999.999999999% sure that it is his second law of motion. 

Hope this helped! :) Please mark brainliest 
5 0
4 years ago
Charge is moving through a wire. An amount of charge Q moves past a particular spot in the wire in an amount of time t to produc
Blababa [14]

We will apply the concept related to the current change given in the same problem. We will divide both currents into two states: the new current and the old current. As the current is the change of the load in a certain time, we will have that the old current is,

I_{old} = \frac{dq}{dt}

If it takes 5 times more time, then we will have the new current is,

I_{new} = \frac{dq}{5dt}

I_{new} = \frac{1}{5}(\frac{dq}{dt})

Replacing the given value of the old current we will have to,

I_{new} = \frac{I_{old}}{5}

Therefore the new current will be \frac{1}{5} the old current.

5 0
4 years ago
A very long, uniformly charged cylinder has radius R and linear charge density λ. Find the cylinder's electric field strength ou
mixer [17]

The cylinder's electric field magnitude, at a distance <em>r</em> from the axis of the cylinder (greater than the cylinder's radius), is equal to E= \frac{\lambda}{2\pi \epsilon_0 \cdot r}

<h3>Further explanation</h3>

Matter is the building block of everything that we encounter in our lives. Matter is made of atoms, which are in turn made of tiny particles which are called electrons, protons, and neutrons. The ammount of these 3 elements, and their topological configuration in the atoms, is what determines what a certain element is (like Carbon, Hydrogen, Iron, etc).

In some cases, some elements may lose or gain some electrons. Regarded that this missing or extra electrons are not very high in number, the material doesn't lose any of its properties, however it will always try to get its number of electrons back to normal. This is when we say that an element has a <em>charge</em>, which is a measure of how much electrons a body needs to get back to normal. A body has positive charge if it lacks electrons, and has negative charge if it has extra electrons.

This charge causes the material to have an Electric field, which is a measure of how much does it attract or repel electrons. In the case of our problem, we need to compute exactly that, the Electric field. In our problem, we have an infinitely long cylinder with a linear charge density \lambda, this means that all parts of the cylinder have the same charge, and due to symmetry, the electric field is constant on the angular and longitudinal directions of the cylinder.

This makes easy to apply Gauss' Law, since for a Gaussian curve in the shape of a concentric cylinder (with a higher radius than that of our charged cylinder) we can write:

\Phi = \frac{\lambda \cdot L}{\epsilon_0}

Where \Phi is called the Electric flux. Since the electric field is constant for a given distance <em>r</em> from the axis of the cylinder we can write that:

\Phi = E \cdot 2\pi r \cdot L

Joining both our expressions we can get that:

E= \frac{\lambda}{2\pi \epsilon_0 \cdot r}

<h3 /><h3>Learn more</h3>
  • Description on Electric fields: brainly.com/question/8971780
  • Relation between electric fields and magnetism: brainly.com/question/2838625
  • How can we use electric charges: brainly.com/question/10427437
<h3>Keywords</h3>

Electrons, protons, electric field, cylinder, electric flux

5 0
3 years ago
Read 2 more answers
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