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3 years ago

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Batman, whose mass is 89.5 kg, is holding on to the free end of a 13.4 m rope, the other end of which is fixed to a tree limb ab

ove. He is able to get the rope in motion as only Batman knows how, eventually getting it to swing enough that he can reach a ledge when the rope makes a 72.4 ◦ angle with the vertical. The acceleration of gravity is 9.8 m/s 2 . How much work was done against the force of gravity in this maneuver?

1 answer:

astra-53 [7]3 years ago

3 0

Answer:

$8.2\times 10^{3}$ J

Explanation:

$L$ = length of the rope connected = 13.4 m

$\theta$ = Angle made by the rope with the vertical = 72.4°

$h$ = height gained by the batman above the reference point

Height gained by the batman above the reference point is given as

$h = L(1 - Cos\theta )$

$m$ = mass of batman = 89.5 kg

$g$ = acceleration due to gravity = 9.8 ms⁻²

Work done against gravity is same as the gravitational potential energy gained by batman and is given as

$W = mgh$

$W = mgL(1 - Cos\theta )$

Inserting the above values

$W = (89.5)(9.8)(13.4)(1 - Cos72.4 )$

$W = 8.2\times 10^{3}$ J

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