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Eduardwww [97]
3 years ago
15

Find the angle of depression

Mathematics
1 answer:
slavikrds [6]3 years ago
6 0

Given:

In triangle ABC, m\angle A=66^\circ, AB=5\text{ mi}.

To find:

The angle of depression from point A to point C.

Solution:

According to angle sum property, the sum of all interior angles of a triangle is 180 degrees.

In triangle ABC,

m\angle A+m\angle B+m\angle C=180^\circ

66^\circ+90^\circ+m\angle C=180^\circ

156^\circ+m\angle C=180^\circ

m\angle C=180^\circ-156^\circ

m\angle C=24^\circ

We know that if a transversal line intersect the two parallel lines, then alternate interior angles are equal. So, the angle of depression from point A to point C is equal to the measure of angle C in triangle ABC.

Therefore, the angle of depression is 24 degrees.

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Gracie owns a deferred annuity. The contract is tied to a market index, which was at 1000 when Gracie purchased the product and
pashok25 [27]

Answer:

Point to point indexed annuity.

Step-by-step explanation:

An indexed annuity is linked to specific index performance. Point to point indexed annuity is the one which gives interest on the basis of index percentage change. The interest credit is calculated by taking the percentage change between the beginning and end points of the index.

6 0
3 years ago
From Midnight to 6 am the temperature rose 8 degrees C. At 6 am the temperature was -21 degrees C. What was the temperature at m
Alika [10]
Hello!

We know that from midnight to 6am the temperature went up 8° and at 6am it was -21°

To find what it was at midnight we have to work backwards

Since it went up we have to subtract 8 from -21

-21 - 8 = -29

The answer is -29°C

Hope this helps!
7 0
3 years ago
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Brainliest for whoever explains
makvit [3.9K]

Answer:

A rectangle.

Step-by-step explanation:

The 2 ends of the rectangular prism are squares while the other 4 sides are rectangles. A cross section parallel to the base would be a rectangle as the base is a rectangle as well.

I hope this helps and if you can please mark brainliest.

7 0
3 years ago
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Use the fact that the mean of a geometric distribution is μ= 1 p and the variance is σ2= q p2. A daily number lottery chooses th
butalik [34]

Answer:

a). The mean = 1000

     The variance = 999,000

     The standard deviation = 999.4999

b). 1000 times , loss

Step-by-step explanation:

The mean of geometric distribution is given as , $\mu = \frac{1}{p}$

And the variance is given by, $\sigma ^2=\frac{q}{p^2}$

Given : $p=\frac{1}{1000}$

             = 0.001

The formulae of mean and variance are :

$\mu = \frac{1}{p}$

$\sigma ^2=\frac{q}{p^2}$

$\sigma ^2=\frac{1-p}{p^2}$

a). Mean =   $\mu = \frac{1}{p}$

              = $\mu = \frac{1}{0.001}$

              = 1000

  Variance =   $\sigma ^2=\frac{1-p}{p^2}$

                  = $\sigma ^2=\frac{1-0.001}{0.001^2}$

                           = 999,000

   The standard deviation is determined by the root of the variance.

    $\sigma = \sqrt{\sigma^2}$

        = $\sqrt{999,000}$ = 999.4999

b). We expect to have play lottery 1000  times to win, because the mean in part (a) is 1000.

When we win the profit is 500 - 1 = 499

When we lose, the profit is -1

Expected value of the mean μ is the summation of a product of each of the possibility x with the probability P(x).

$\mu=\Sigma\ x\ P(x)= 499 \times 0.001+(-1) \times (1-0.001)$

  = $ 0.50

Since the answer is negative, we are expected to make a loss.

4 0
3 years ago
Based on an indication that mean daily car rental rates may be higher for Boston than for Dallas, a survey of eight car rental c
Elina [12.6K]

Answer:

t=\frac{(47 -44)-(0)}{3\sqrt{\frac{1}{8}+\frac{1}{9}}}=2.058

The degrees of freedom are:

df=8+9-2=15

And the p value would be:

p_v =P(t_{15}>2.058) =0.0287

Since we have a p value lower than the significance level given of 0.05 we can reject the null hypothesis and we can conclude that the true mean for car rental rates in Boston are significantly higher than those in Dallas

Step-by-step explanation:

Data given

n_1 =8 represent the sample size for group Boston

n_2 =9 represent the sample size for group Dallas

\bar X_1 =47 represent the sample mean for the group Boston

\bar X_2 =44 represent the sample mean for the group Dallas

s_1=3 represent the sample standard deviation for group Boston

s_2=3 represent the sample standard deviation for group Dallas

We can assume that we have independent samples from two normal distributions with equal variances and that is:

\sigma^2_1 =\sigma^2_2 =\sigma^2

Let the subindex 1 for Boston and 2 for Dallas we want to check the following hypothesis:

Null hypothesis: \mu_1 \leq \mu_2

Alternative hypothesis: \mu_1 > \mu_2

The statistic is given by this formula:

t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}

Where t follows a t student distribution with n_1+n_2 -2 degrees of freedom and the pooled variance S^2_p is given by this formula:

\S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}

Replacing we got:

\S^2_p =\frac{(8-1)(3)^2 +(9 -1)(3)^2}{8 +9 -2}=9

And the deviation would be just the square root of the variance:

S_p=3

The statitsic would be:

t=\frac{(47 -44)-(0)}{3\sqrt{\frac{1}{8}+\frac{1}{9}}}=2.058

The degrees of freedom are:

df=8+9-2=15

And the p value would be:

p_v =P(t_{15}>2.058) =0.0287

Since we have a p value lower than the significance level given of 0.05 we can reject the null hypothesis and we can conclude that the true mean for car rental rates in Boston are significantly higher than those in Dallas

5 0
3 years ago
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