A school has 617 students. Each class has between 28 and 32 students. Which is the best estimate of the number of classes in the
1 answer:
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<h3>Answer:</h3>
A. +-5x+14x+-35
+9x-35
B.
C.
D.
Step-by-step explanation:
A. (3x*2x)+(3x*-5)+(7*2x)+(7*-5)
Multiply and simplify.
+9x-35
B. ()+(
-3x)+(2x
)+(2x
)
Multiply and simplify.
C.
Multiply and simplify.
D.
Multiply and simplify.
I hope this helps!
But you should really do this yourself.
Answer:
We conclude that young women are delaying marriage and marrying at a later age.
Step-by-step explanation:
We are given that the average age of brides marrying for the first time is 23.9 years with a population standard deviation of 4.2 years.
The sociologist randomly samples 100 marriage records and determines the average age of the first time brides is 24.9 years.
Let = <u><em>average age of brides marrying for the first time.</em></u>
So, Null Hypothesis, :
= 23.9 years {means that young women are not delaying marriage and marrying at a later age}
Alternate Hypothesis, :
> 23.9 years {means that young women are delaying marriage and marrying at a later age}
The test statistics that would be used here <u>One-sample z test statistics</u> as we know about the population standard deviation;
T.S. = ~ N(0,1)
where, = sample average age of the first time brides = 24.9 years
= population standard deviation = 4.2 years
n = sample of marriage records = 100
So, <u><em>the test statistics</em></u> =
= 2.381
The value of z test statistics is 2.381.
<u>Now, at 1% significance level the z table gives critical value of and 2.326 for right-tailed test.</u>
Since our test statistic is more than the critical value of z as 2.381 > 2.326, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u>we reject our null hypothesis</u>.
Therefore, we conclude that young women are delaying marriage and marrying at a later age.