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3 years ago

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In two years, Winston who is eight years older than Xavier, will be twice as old as Xavier. How old is each one now?

1 answer:

MA_775_DIABLO [31]3 years ago

7 0

W=winston's age
x=xavier's age

winston is 8 years older than xavier
w=8+x

in 2 years, winston will be twice as old as xavier
w+2=2(x+2)

we have
w=8+x and
w+2=2(x+2)
subsitute 8+x for w

w+2=2(w+2)
8+x+2=2(x+2)
x+10=2(x+2)
x+10=2x+4
minus x both sides
10=x+4
minus 4 both sides
6=x

sub back
w=8+x
w=8+6
w=14

winston is 14 years old now
xavier is 6 years old now

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3 years ago

Given the below sequence:

kvasek [131]

Answer:

a) The next three terms are -1,-3,-5,-7,-9,-11,-13

b) This is arithmetic sequence

C) The difference of second term and first term is -2 in given sequence so the given sequence is an arithmetic sequence.

d) The 27 th term is -53

Step-by-step explanation:

a) the given sequence is arithmetic sequence

the difference of second term and first term is -2

given sequence is -1,-3,-5,-7.....

the nth term in arithmetic sequence

$t_{n} = a+(n-1)d$

First term is a = -1 and difference is d = -2

finding fifth term is

$t_{5} = -1 +(5-1)(-2)$

$t_{5} = -1-8 =-9$

finding sixth term is

$t_{6} = -1 +(6-1)(-2)$

$t_{6} = -1-10 =-11$

finding seventh term is

$t_{7} = -1 + (7-1)(-2)$

$t_{7} = -1 -12 =-13$

The next three terms are -9,-11,-13

The given sequence is -1,-3,-5,-7,-9,-11,-13

b) This is arithmetic sequence.

C) because the difference of second term and first term is -2 so the given sequence is arithmetic sequence.

d) by using nth term formula in arithmetic sequence

$t_{n} = a+(n-1)d$

a= -1 and d =-2

<u>find 27 t h term :-</u>

<u></u> $t_{27} = -1 + (27-1)(-2) = -1-52=-53$ <u></u>

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Answer:

-8

Step-by-step explanation:

-8m⁴ n⁴

m = 0.5 = 1/2

n = 2

Substitute

-8 * (1/2)⁴ * (2)⁴

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